PostgreSQL计算行之间的差异

Question

我尝试使用查询计算字段中行之间的差异:

Illustrations:
input:year,month,fixes
output:increase

     year | month | fixes    | increase
    ------+-------+----------+-----------
     2006 | 04    |       1  | 0
     2006 | 05    |       4  | 3
     2006 | 06    |       3  | -1

通过修复中相邻行之间的差异来增加列作为输出.

Answer 1

这是窗口函数的用途:

select year, 
       month,
       fixes,
       fixes - lag(fixes) over (order by year, month) as increase,
from the_table;

有关详细信息,请参阅手册:http:
//www.postgresql.org/docs/current/static/tutorial-window.html