com*_*tta 9 java hibernate jpa
我的jpa看起来如下
public class TESTClass implements Serializable {
...
private String name;
@EmbeddedId
protected IssTESTPK issTESTPK;
@ManyToOne(optional=false)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", nullable=false, insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUM", referencedColumnName="SURVEY_NUM", nullable=false, insertable=false, updatable=false)})
private IssDivision issDivision;
}
Run Code Online (Sandbox Code Playgroud)
如果我更改为'name'并调用merge,它可以更新到数据库,但是当我更改issDivision并调用merge时,它不会更新数据库.怎么解决这个?
是否与之相关,因为我使用的是embededId(复合主键)?
如果我设置upadted = true,我得到以下错误
ERROR - ContextLoader.initWebApplicationContext(215) | Context initialization fa
iled
org.springframework.beans.factory.BeanCreationException: Error creating bean wit
h name 'sessionFactory' defined in ServletContext resource [/WEB-INF/application
Context.xml]: Invocation of init method failed; nested exception is org.hibernat
e.MappingException: Repeated column in mapping for entity: com.compay.test.model
.TESTClass column: SURVEY_NUM (should be mapped with insert="false" update="fa
lse")
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.initializeBean(AbstractAutowireCapableBeanFactory.java:1338)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.doCreateBean(AbstractAutowireCapableBeanFactory.java:473)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory$1.run(AbstractAutowireCapableBeanFactory.java:409)
at java.security.AccessController.doPrivileged(Native Method)
at org.springframework.beans.factory.support.AbstractAutowireCapableBean
Factory.createBean(AbstractAutowireCapableBeanFactory.java:380)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getOb
ject(AbstractBeanFactory.java:264)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistr
y.getSingleton(DefaultSingletonBeanRegistry.java:222)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBe
an(AbstractBeanFactory.java:261)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean
(AbstractBeanFactory.java:185)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean
(AbstractBeanFactory.java:164)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.
preInstantiateSingletons(DefaultListableBeanFactory.java:423)
at org.springframework.context.support.AbstractApplicationContext.finish
BeanFactoryInitialization(AbstractApplicationContext.java:728)
at org.springframework.context.support.AbstractApplicationContext.refres
h(AbstractApplicationContext.java:380)
at org.springframework.web.context.ContextLoader.createWebApplicationCon
text(ContextLoader.java:255)
at org.springframework.web.context.ContextLoader.initWebApplicationConte
xt(ContextLoader.java:199)
at org.springframework.web.context.ContextLoaderListener.contextInitiali
zed(ContextLoaderListener.java:45)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContex
t.java:3843)
at org.apache.catalina.core.StandardContext.start(StandardContext.java:4
342)
at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase
.java:791)
at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:77
1)
at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:525)
at org.apache.catalina.startup.HostConfig.deployDescriptor(HostConfig.ja
va:627)
at org.apache.catalina.startup.HostConfig.deployDescriptors(HostConfig.j
ava:553)
at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:488
)
at org.apache.catalina.startup.HostConfig.start(HostConfig.java:1149)
at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java
:311)
at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Lifecycl
eSupport.java:117)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1053)
at org.apache.catalina.core.StandardHost.start(StandardHost.java:719)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443
)
at org.apache.catalina.core.StandardService.start(StandardService.java:5
16)
at org.apache.catalina.core.StandardServer.start(StandardServer.java:710
)
at org.apache.catalina.startup.Catalina.start(Catalina.java:578)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.
Run Code Online (Sandbox Code Playgroud)
Art*_*ald 15
好的,我们等着瞧
您的异常(和着名)消息是
repeated column in mapping for entity:
column: SURVEY_NUM (should be mapped with insert="false" update="false")
Run Code Online (Sandbox Code Playgroud)
SURVEY_NUM专栏在哪里?
1º issDivision字段存储称为SURVEY_NUM一个外键列
@ManyToOne
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUM", referencedColumnName="SURVEY_NUM", insertable=false, updatable=false)})
private IssDivision issDivision;
Run Code Online (Sandbox Code Playgroud)
现在,请参阅以下映射(请参阅id和accountNumber共享同一列)
@Entity
public class Account {
private Integer id;
private Integer accountNumber;
@Id
@Column(name="ACCOUNT_NUMBER")
public Integer getId() {
return this.id;
}
@Column(name="ACCOUNT_NUMBER")
public Integer getAccountNumber() {
return this.accountNumber;
}
}
Run Code Online (Sandbox Code Playgroud)
现在让我们这样做
Account account = new Account();
account.setId(127359);
account.setAccountNumber(null);
entityManager.persist(account);
Run Code Online (Sandbox Code Playgroud)
Hibernate会问你
我应该坚持哪个属性是否两个属性共享同一列?正如我所看到的,id属性存储一个非null值,accountNumber存储一个空值.
我应该执行这样的查询???
INSERT INTO ACCOUNT (ACCOUNT_NUMBER, ACCOUNT_NUMBER) VALUES (127359, NULL);
Run Code Online (Sandbox Code Playgroud)
它没有任何意义.因此,它是一个错误的SQL查询;
因此,你会看到这个好消息
重复列...等等,等等,等等...(应使用insert ="false"update ="false"进行映射)
所以我想你的复合主键IssTESTPK也存储一个名为SURVEY_NUM的列.并且将复合主键属性定义为insert ="false"update ="false" 并不是一个好主意.避免很多头痛.
请记住:当多个属性共享同一列时,将其中一个定义为insertable = false,updatable = false.没有别的.
我认为你的复合主键类看起来应该是这样的
@Embeddable
public class IssTESTPK implements Serializable {
// Ops... Our missing field which causes our Exception (repeated column... blah, blah, blah...)
@Column(name="SURVEY_NUM", nullable=false)
private Integer property;
private Integer otherProperty;
private Integer anotherProperty;
// required no-arg constructor
public IssTESTPK() {}
// You must implement equals and hashcode
public boolean equals(Object o) {
if(o == null)
return false;
if(!(o instanceof IssTESTPK))
return false;
IssTESTPK other = (IssTESTPK) o;
if(!(getProperty().equals(other.getProperty())))
return false;
if(!(getOtherProperty().equals(other.getOtherProperty())))
return false;
if(!(getAnotherProperty().equals(other.getAnotherProperty())))
return false;
return true;
}
// NetBeans or Eclipse will worry about it
public int hashcode() {
// hashcode code goes here
}
}
Run Code Online (Sandbox Code Playgroud)
UPDATE
继续之前
Hibernate 不支持自动生成复合主键
您必须在保存之前提供其值.记在心上
让我们看一下Employee复合主键
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER")
private String employeeNumber;
@Column(name="SURVEY_NUMBER")
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
Run Code Online (Sandbox Code Playgroud)
1º在保存员工之前,您必须提供其值.如上所述,Hibernate不支持自动生成复合主键
2ºHibernate不允许更新(复合)主键它没有意义.
3º其值不能为空
因此,根据上述情况,我们的EmployeeId可以写成
@Embeddable
public class EmployeeId implements Serializable {
@Column(name="EMPLOYEE_NUMBER", nullable=false, updatable=false)
private String employeeNumber;
@Column(name="SURVEY_NUMBER", nullable=false, updatable=false)
private BigInteger surveyNumber;
// getter's and setter's
// equals and hashcode
}
Run Code Online (Sandbox Code Playgroud)
如上所述
当多个属性共享同一列时,将其中一个定义为insertable = false,updatable = false.没有其他的
但是,我们不能标记复合主键属性作为插入=假,可更新=假,因为Hibernate使用它来拯救我们的实体
由于Hibernate将使用名为surveyNumber(及其SURVEY_NUMBER列)的复合主键属性对数据库执行SQL操作,我们需要将@ManyToOne除法属性(及其外键列名为SURVEY_NUMBER)重写为insertable = false,可更新= FALSE
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE"),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
Run Code Online (Sandbox Code Playgroud)
4º当你有一个复合外键时,我们不能混合 insertable-non-insertable或updatable-non-updatable.
就像是
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
// I can be updatable
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false),
// And i can be insertable
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", updatable=false)})
private Division division;
Run Code Online (Sandbox Code Playgroud)
否则,Hibernate会抱怨
不允许在属性中混合可插入和不可插入的列
因此,它的复合外键列DIVISION_CODE 也应标记为insertable = false,updatable = false以避免上面显示的异常
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
Run Code Online (Sandbox Code Playgroud)
由于我们不能再更新DIVISION_CODE列,因此我们的除法属性就像一个常量.然后,您考虑创建一个名为divisionCode的新属性,以便更改DIVISION_CODE列,如下所示
// Employee.java
@ManyToOne(fetch=FetchType.LAZY)
@JoinColumns({
@JoinColumn(name="DIVISION_CODE", referencedColumnName="DIVISION_CODE", insertable=false, updatable=false),
@JoinColumn(name="SURVEY_NUMBER", referencedColumnName="SURVEY_NUMBER", insertable=false, updatable=false)})
private Division division;
// Wow, now i expect i can change the value of DIVISION_CODE column
@Column(name="DIVISION_CODE")
private BigInteger divisionCode;
Run Code Online (Sandbox Code Playgroud)
好的,我们等着瞧.假设我们有以下DIVISION TABLE
DIVISION TABLE
DIVISION_CODE SURVEY_NUMBER
1 10
2 11
3 12
4 13
5 14
Run Code Online (Sandbox Code Playgroud)
记住:Division和Employee之间存在外键约束
你想到了
由于insertable = false,updatable = false,我无法更改除法属性.但我可以更改divisionCode属性(及其DIVISION_CODE列)作为更改名为DIVISION_CODE的外键列的方法
您执行以下代码
employee.setDivisionCode(7);
哇,见上面的DIVISION_TABLE.DIVISION_CODE列中的某些值是否等于7?
答案很清楚:没有(你会看到一个约束违规)
所以,这是一个不一致的映射.Hibernate不允许它.
问候,
| 归档时间: |
|
| 查看次数: |
31790 次 |
| 最近记录: |