Java - 只读取文件的第一行

Question

我只想读取文本文件的第一行,并将第一行放在字符串数组中.

这是我所拥有的,但它读取整个文件.

myTextFile中的ex文本:

Header1,Header2,Header3,Header4,Header5
1,2,3,4,5
6,7,8,9,10





String line= System.getProperty("line.separator");
String strArray[] = new String[5];


String text = null;
BufferedReader brTest = new BufferedReader(new FileReader(myTextFile));
    text = brTest .readLine();
        while (text != line) {
            System.out.println("text = " + text );
             strArray= text.split(",");
         }

Answer 1

如果我了解你,那么

String text = brTest.readLine();
// Stop. text is the first line.
System.out.println(text);
String[] strArray = text.split(",");
System.out.println(Arrays.toString(strArray));

Answer 2

用BufferedReader.readLine() 获得的第一行.

BufferedReader brTest = new BufferedReader(new FileReader(myTextFile));
    text = brTest .readLine();
   System.out.println("Firstline is : " + text);

Answer 3

使用 Java 8，java.nio您还可以执行以下操作：

String myTextFile = "path/to/your/file.txt";
Path myPath = Paths.get(myTextFile);
String[] strArray = Files.lines(myPath)
    .map(s -> s.split(","))
    .findFirst()
    .get();

如果TAsks假设是正确的，您可以通过额外的

.filter(s -> !s.equals(""))