Duo*_*duo 4 javascript resolve angularjs angular-ui-router
$stateProvider.state('home', {
url: '/',
resolve: {
person: function() {
return 'good'
}
}
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像上面的状态配置一样,如何在$ stateChangeSuccess回调函数中获取'person'值?
$rootScope.$on('$stateChangeSuccess',
function(event, toState, toParams, fromState, fromParams) {
// I want get the 'person' value in this function, what should I do?
});
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tax*_*ian 13
我们遇到了同样的问题.我们依靠ui-router的一些内部实现细节来解决它; 这确实意味着它可能会在未来的angular版本中破坏,但这是我们使用的函数:
function annotatedStateObject(state, $current) {
state = _.extend({}, state);
var resolveData = $current.locals.resolve.$$values;
state.params = resolveData.$stateParams;
state.resolve = _.omit(resolveData, '$stateParams');
state.includes = $current.includes;
return state;
}
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这将获得params,includes和所有(已解决的)解析对象.我们在回调中使用它,如下所示:
$scope.$on('$stateChangeSuccess', function(event, toState, toParams, fromState, fromParams) {
toState = annotatedStateObject(toState, $state.$current);
var person = toState.resolve.person;
}
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我希望有所帮助!