Mongodb聚合管道如何限制组推

cha*_*hne 22 mongodb mongodb-query aggregation-framework

我无法使用聚合管道限制组函数中推送元素的数量.这可能吗?小例子:

数据:

[
    {
        "submitted": date,
        "loc": {
            "lng": 13.739251,
            "lat": 51.049893
        },
        "name": "first",
        "preview": "my first"
    },
    {
        "submitted": date,
        "loc": {
            "lng": 13.639241,
            "lat": 51.149883
        },
        "name": "second",
        "preview": "my second"
    },
    {
        "submitted": date,
        "loc": {
            "lng": 13.715422,
            "lat": 51.056384
        },
        "name": "nearpoint2",
        "preview": "my nearpoint2"
    }
]
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这是我的聚合管道:

  var pipeline = [{
    //I want to limit the data to a certain area
    $match: {
        loc: {
            $geoWithin: {
                $box: [
                    [locBottomLeft.lng, locBottomLeft.lat],
                    [locUpperRight.lng, locUpperRight.lat]
                ]
            }
        }
    }
},
// I just want to get the latest entries  
{
    $sort: {
        submitted: -1
    }
},
// I group by name
{
    $group: {
        _id: "$name",
        < --get name
        submitted: {
            $max: "$submitted"
        },
        < --get the latest date
        locs: {
            $push: "$loc"
        },
        < --push every loc into an array THIS SHOULD BE LIMITED TO AN AMOUNT 5 or 10
        preview: {
            $first: "$preview"
        }
    }
},
//Limit the query to at least 10 entries.
{
    $limit: 10
}
];
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如何将locs数组限制为10任何其他大小?我想用的东西$each$slice,但似乎并没有工作.

sty*_*ane 19

假设左下角坐标和右上角坐标分别为[0, 0][100, 100].从MongoDB 3.2中,您可以使用$slice运算符返回您想要的数组的子集.

db.collection.aggregate([
    { "$match": { 
        "loc": { 
            "$geoWithin":  { 
                "$box": [ 
                    [0, 0], 
                    [100, 100]
                ]
            }
        }}
    }},
    { "$group": { 
        "_id": "$name",
        "submitted": { "$max": "$submitted" }, 
        "preview": { "$first": "$preview" }
        "locs": { "$push": "$loc" }
    }}, 
    { "$project": { 
        "locs": { "$slice": [ "$locs", 5 ] },
        "preview": 1,
        "submitted": 1
    }},
    { "$limit": 10 }
])
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  • 有没有办法直接做到这一点? (2认同)

Xav*_*hot 5

从 开始Mongo 5.2,这是新$topN聚合累加器的完美用例:

// { submitted: ISODate("2021-12-05"), group: "group1", value: "plop" }
// { submitted: ISODate("2021-12-07"), group: "group2", value: "smthg" }
// { submitted: ISODate("2021-12-06"), group: "group1", value: "world" }
// { submitted: ISODate("2021-12-12"), group: "group1", value: "hello" }
db.collection.aggregate([
  { $group: {
    _id: "$group",
    top: { $topN: { n: 2, sortBy: { submitted: -1 }, output: "$value" } }
  }}
])
// { _id: "group1", top: [ "hello", "world" ] }
// { _id: "group2", top: [ "smthg" ] }
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这适用于$topN以下组累积:

  • 每组取前 2 个 ( n: 2) 元素
  • 前 2 个,定义为sortBy: { submitted: -1 }(按时间倒序)
  • 并为每个分组记录提取字段value( output: "$value")