PHP扩展迭代数组

Question

我开始编写一个PHP扩展,希望能够了解如何遍历传递的数组(目的是通过值更改数据值).首选方法是for循环,以便我可以将array1与array2数据匹配,例如array1 [0]链接到array2 [0],[1]与[1]等...

有人能帮忙吗？

modarray.c

#ifdef HAVE_CONFIG_H
#include "config.h"
#endif
#include "php.h"

extern zend_module_entry modarray_module_entry;
#define phpext_modarray_ptr &modarray_module_entry

PHP_FUNCTION(modarray);

static function_entry modarray_functions[] = {
    PHP_FE(modarray, NULL)
    PHP_FE_END
};

zend_module_entry modarray_module_entry = {
  STANDARD_MODULE_HEADER,
  "modarray",
  modarray_functions,
  NULL,
  NULL,
  NULL,
  NULL,
  NULL,
  "0.1",
  STANDARD_MODULE_PROPERTIES
};

ZEND_GET_MODULE(modarray)

PHP_FUNCTION(modarray)
{
  zval *val, *val2;

  if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "z|z", &val, &val2) == FAILURE){
    return;
  }

  SEPARATE_ZVAL(&val);
  SEPARATE_ZVAL(&val2);

  array_init(return_value);

  zval_add_ref(&val);
  zval_add_ref(&val2);
  add_next_index_zval(return_value, val);
  add_next_index_zval(return_value, val2);
}

PHP代码

<?php
$array1 = array(1,2,3,4);
$array2 = array(5,6,7,8);
echo '<pre>';
print_r(modarray($array1,$array2));
echo '</pre>';
?>

PHP输出

Array
(
    [0] => Array
        (
            [0] => 1
            [1] => 2
            [2] => 3
            [3] => 4
        )

    [1] => Array
        (
            [0] => 5
            [1] => 6
            [2] => 7
            [3] => 8
        )

)

Answer 1

有两种方法可以做到这一点，一种是使用迭代 API 完全“手动”：

\n\n

HashPosition pos;\nzval *collection, **arg;\nuint hash_key_type;\nuint string_key_len;\nulong int_key;\nchar *string_key = NULL;\n\n... get the collection from somewhere, e.g. argument parsing ...\n\nwhile (!EG(exception) && zend_hash_get_current_data_ex(Z_ARRVAL_P(collection), (void **)&arg, &pos) == SUCCESS) {\n    zend_hash_internal_pointer_reset_ex(Z_ARRVAL_P(collection), &pos);\n    MAKE_STD_ZVAL(key);\n    hash_key_type = zend_hash_get_current_key_ex(Z_ARRVAL_P(collection), &string_key, &string_key_len, &int_key, 0, &pos);\n\n    // Invoke e.g. zend_hash_update\n\n    zend_hash_move_forward_ex(Z_ARRVAL_P(collection), &pos);\n}\n

\n\n

首选的替代方案是使用三个zend_hash_apply*()带有回调的函数，这被认为更优雅：

\n\n

static int replace_value(zval **arg, zval ****params TSRMLS_DC)\n{\n    add_next_index_zval(params, val);\n\n    return ZEND_HASH_APPLY_REMOVE;\n}\n\nzval *in, ***out;\n... fill in from somewhere from somewhere, e.g. argument parsing ...\narray_init(**out);\nzend_hash_apply_with_argument(Z_ARRVAL_P(collection, (apply_func_arg_t) replace_value, params TSRMLS_CC);\n

\n\n

注意：我没有在本地测试这两个片段，而是从不同的地方复制了它。

\n