在python中使用负数

Question

我是编程类概念的学生.该实验室由TA运营,今天在实验室中他给了我们一个简单的小程序来构建.它是一个可以通过添加繁殖的地方.无论如何,他让我们使用绝对来避免用底片打破前卫.我快速地将它掀起,然后和他争论了10分钟这是不好的数学.它是,4*-5不等于20,它等于-20.他说他真的不在乎这一点,而且无论如何都要让编程处理负面因素太难了.所以我的问题是如何解决这个问题.

这是我上交的编程:

#get user input of numbers as variables

numa, numb = input("please give 2 numbers to multiply seperated with a comma:")

#standing variables
total = 0
count = 0

#output the total
while (count< abs(numb)):
    total = total + numa
    count = count + 1

#testing statements
if (numa, numb <= 0):
    print abs(total)
else:
    print total

我想做的没有绝对,但每次我输入负数我得到一个大胖子鹅.我知道有一些简单的方法可以做到,我找不到它.

Answer 1

也许你会用这样的东西来完成这个

text = raw_input("please give 2 numbers to multiply separated with a comma:")
split_text = text.split(',')
a = int(split_text[0])
b = int(split_text[1])
# The last three lines could be written: a, b = map(int, text.split(','))
# but you may find the code I used a bit easier to understand for now.

if b > 0:
    num_times = b
else:
    num_times = -b

total = 0
# While loops with counters basically should not be used, so I replaced the loop 
# with a for loop. Using a while loop at all is rare.
for i in xrange(num_times):
    total += a 
    # We do this a times, giving us total == a * abs(b)

if b < 0:
    # If b is negative, adjust the total to reflect this.
    total = -total

print total

或者可能

a * b