如何使用Browserify和iOS JavaScriptCore

Question

给定一个不依赖于任何Node.js功能的Node.js模块,除了modules(export/require)如何使用JS核心从Objective-C或Swift访问其函数？

示例"模块":

var compute = function compute(number) {
  return 2 * number
};

exports.compute = compute;

Browserified bundle(bundle.js):

(function e(t,n,r){function s(o,u){if(!n[o]){if(!t[o]){var a=typeof require=="function"&&require;if(!u&&a)return a(o,!0);if(i)return i(o,!0);throw new Error("Cannot find module '"+o+"'")}var f=n[o]={exports:{}};t[o][0].call(f.exports,function(e){var n=t[o][1][e];return s(n?n:e)},f,f.exports,e,t,n,r)}return n[o].exports}var i=typeof require=="function"&&require;for(var o=0;o<r.length;o++)s(r[o]);return s})({1:[function(require,module,exports){

var compute = function compute(number) {
  return 2 * number
};

exports.compute = compute;

},{}]},{},[1])

SWIFT代码:

代码波纹管似乎没有能够找到compute中的函数bundle.js-的result是NaN.

var path = b.pathForResource("bundle", ofType: "js")
var source : String = NSString.stringWithContentsOfFile(path, encoding: NSUTF8StringEncoding, error: nil)
var context = JSContext()
context.evaluateScript(source)
let compute = context.objectForKeyedSubscript("compute")
let value = compute.callWithArguments([42])
var result = value.toNumber()

如何访问"浏览器化"JavaScript函数？

Answer 1

thejh对相关问题的回答解释说，默认情况下，browserify 不允许您从 browserified 代码外部访问函数和模块。他的回答展示了如何在“窗口”级别定义包装函数，然后可以从 ObjC / Swift 调用该函数