什么是makeObjectsPerformSelector的快速等价物？

Question

在Objective-C中,我使用此代码删除任何子视图:

[self.view.subviews makeObjectsPerformSelector:@selector(removeFromSuperview)];

但是如何在swift中使用它呢？我看到苹果文档在swift中使用该方法

func makeObjectsPerformSelector(_ aSelector: Selector)

但是当我尝试它时,我收到一个错误: 'AnyObject[]' does not have a member named 'makeObjectsPerformSelector'

有没有办法删除swift中的子视图？

Answer 1

更新了Swift 2.0(Xcode 7)

用途forEach:

self.view.subviews.forEach { subview in
    subview.removeFromSuperview()
}

或者像这样:

view.subviews.forEach { $0.removeFromSuperview() }