Ale*_*lli 93
使用Python标准库的linecache模块:
line = linecache.getline(thefilename, 33)
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应该做你想要的.您甚至不需要打开文件 - linecache为您完成所有操作!
小智 6
此代码将打开文件,读取行并打印它.
# Open and read file into buffer
f = open(file,"r")
lines = f.readlines()
# If we need to read line 33, and assign it to some variable
x = lines[33]
print(x)
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一个不会读取更多文件的解决方案是
from itertools import islice
line_number = 34
with open(filename) as f:
# Adjust index since Python/islice indexes from 0 and the first
# line of a file is line 1
line = next(islice(f, line_number - 1, line_number))
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一个非常简单的解决方案是
line_number = 34
with open(filename) as f:
f.readlines()[line_number - 1]
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