播放框架:Slick不知道如何映射给定的类型

Question

我试图在播放框架中使用光滑,但即使是最简单的例子也在苦苦挣扎.

这是我的代码:

case class Account (
  id: Int,
  email: String,
  password: String,
  permission: String
)

class Accounts(tag: Tag) extends Table[Account](tag, "account") {
  def id = column[Int]("id")
  def email = column[String]("email")
  def password = column[String]("password")
  def permission = column[String]("permission")

  def * = (id, email, password, permission)
}

当我编译这个时,我收到以下错误:

play.PlayExceptions$CompilationException: Compilation error[No matching Shape found.
Slick does not know how to map the given types.
Possible causes: T in Table[T] does not match your * projection. Or you use an unsupported type in a Query (e.g. scala List).
  Required level: scala.slick.lifted.ShapeLevel.Flat
     Source type: (scala.slick.lifted.Column[Int], scala.slick.lifted.Column[String], scala.slick.lifted.Column[String], scala.slick.lifted.Column[String])
   Unpacked type: models.Account
     Packed type: Any
]

任何人都可以告诉我,如果我在这里有问题吗？

谢谢

更多详情:

• 斯卡拉2.10
• 光滑2.0.2
• Play-slick 0.6.0.1
• Play Framework 2.3.1

Answer 1

我发现了这个问题.我有一个相互矛盾的伴侣对象

如果您有伴随对象,则需要对*投影使用略有不同的语法:

def * = (id, email, password, permission) <> ((Account.apply _).tupled, Account.unapply)