kri*_*aex 84
注意:我将在即将到来的段落中过度简化,甚至可能会略微伪造.有关更多详细信息,请参阅Martin Fowler的网站.
mock是一个替换真实类的虚拟类,为每个方法调用返回null或0.如果您需要复杂类的虚拟实例,否则您将使用模拟,否则将使用外部资源,如网络连接,文件或数据库,或者可能使用许多其他对象.模拟的优点是可以将被测试的类与系统的其余部分隔离开来.
存根也是一个虚拟类,为某些被测请求提供一些更具体,准备或预先录制的重放结果.你可以说存根是一个花哨的模拟.在Spock中,您经常会阅读存根方法.
间谍是真实对象和存根之间的混合体,即它基本上是真实对象,其中一些(不是全部)方法被存根方法遮蔽.非存根方法只是路由到原始对象.通过这种方式,您可以拥有"廉价"或琐碎方法的原始行为以及"昂贵"或复杂方法的虚假行为.
更新2017-02-06:实际上,用户mikhail的回答比Spock更具体,而不是我原来的回答.因此,在Spock的范围内,他描述的内容是正确的,但这并不能篡改我的一般答案:
现在这里是一个可执行的示例测试,展示了什么是可能的,什么是不可能的.它比mikhail的片段更有启发性.非常感谢他鼓励我改进自己的答案!:-)
package de.scrum_master.stackoverflow
import org.spockframework.mock.TooFewInvocationsError
import org.spockframework.runtime.InvalidSpecException
import spock.lang.FailsWith
import spock.lang.Specification
class MockStubSpyTest extends Specification {
static class Publisher {
List<Subscriber> subscribers = new ArrayList<>()
void addSubscriber(Subscriber subscriber) {
subscribers.add(subscriber)
}
void send(String message) {
for (Subscriber subscriber : subscribers)
subscriber.receive(message);
}
}
static interface Subscriber {
String receive(String message)
}
static class MySubscriber implements Subscriber {
@Override
String receive(String message) {
if (message ==~ /[A-Za-z ]+/)
return "ok"
return "uh-oh"
}
}
Subscriber realSubscriber1 = new MySubscriber()
Subscriber realSubscriber2 = new MySubscriber()
Publisher publisher = new Publisher(subscribers: [realSubscriber1, realSubscriber2])
def "Real objects can be tested normally"() {
expect:
realSubscriber1.receive("Hello subscribers") == "ok"
realSubscriber1.receive("Anyone there?") == "uh-oh"
}
@FailsWith(TooFewInvocationsError)
def "Real objects cannot have interactions"() {
when:
publisher.send("Hello subscribers")
publisher.send("Anyone there?")
then:
2 * realSubscriber1.receive(_)
}
def "Stubs can simulate behaviour"() {
given:
def stubSubscriber = Stub(Subscriber) {
receive(_) >>> ["hey", "ho"]
}
expect:
stubSubscriber.receive("Hello subscribers") == "hey"
stubSubscriber.receive("Anyone there?") == "ho"
stubSubscriber.receive("What else?") == "ho"
}
@FailsWith(InvalidSpecException)
def "Stubs cannot have interactions"() {
given: "stubbed subscriber registered with publisher"
def stubSubscriber = Stub(Subscriber) {
receive(_) >> "hey"
}
publisher.addSubscriber(stubSubscriber)
when:
publisher.send("Hello subscribers")
publisher.send("Anyone there?")
then:
2 * stubSubscriber.receive(_)
}
def "Mocks can simulate behaviour and have interactions"() {
given:
def mockSubscriber = Mock(Subscriber) {
3 * receive(_) >>> ["hey", "ho"]
}
publisher.addSubscriber(mockSubscriber)
when:
publisher.send("Hello subscribers")
publisher.send("Anyone there?")
then: "check interactions"
1 * mockSubscriber.receive("Hello subscribers")
1 * mockSubscriber.receive("Anyone there?")
and: "check behaviour exactly 3 times"
mockSubscriber.receive("foo") == "hey"
mockSubscriber.receive("bar") == "ho"
mockSubscriber.receive("zot") == "ho"
}
def "Spies can have interactions"() {
given:
def spySubscriber = Spy(MySubscriber)
publisher.addSubscriber(spySubscriber)
when:
publisher.send("Hello subscribers")
publisher.send("Anyone there?")
then: "check interactions"
1 * spySubscriber.receive("Hello subscribers")
1 * spySubscriber.receive("Anyone there?")
and: "check behaviour for real object (a spy is not a mock!)"
spySubscriber.receive("Hello subscribers") == "ok"
spySubscriber.receive("Anyone there?") == "uh-oh"
}
def "Spies can modify behaviour and have interactions"() {
given:
def spyPublisher = Spy(Publisher) {
send(_) >> { String message -> callRealMethodWithArgs("#" + message) }
}
def mockSubscriber = Mock(MySubscriber)
spyPublisher.addSubscriber(mockSubscriber)
when:
spyPublisher.send("Hello subscribers")
spyPublisher.send("Anyone there?")
then: "check interactions"
1 * mockSubscriber.receive("#Hello subscribers")
1 * mockSubscriber.receive("#Anyone there?")
}
}
Run Code Online (Sandbox Code Playgroud)
mik*_*ail 44
问题出在Spock框架的背景下,我不相信当前的答案会考虑到这一点.
基于Spock文档(示例定制,我自己的措辞添加):
存根: 用于使协作者以某种方式响应方法调用.在对方法进行存根化时,您不关心该方法的调用次数和次数; 你只是希望它在被调用时返回一些值,或者执行一些副作用.
subscriber.receive(_) >> "ok" // subscriber is a Stub()
Run Code Online (Sandbox Code Playgroud)
模拟: 用于描述规范下的对象与其协作者之间的交互.
def "should send message to subscriber"() {
when:
publisher.send("hello")
then:
1 * subscriber.receive("hello") // subscriber is a Mock()
}
Run Code Online (Sandbox Code Playgroud)
模拟可以充当模拟和存根:
1 * subscriber.receive("message1") >> "ok" // subscriber is a Mock()
Run Code Online (Sandbox Code Playgroud)
间谍: 总是基于一个真实的对象与原始方法做真实的事情.可以像Stub一样使用来更改select方法的返回值.可以像模拟一样用来描述交互.
def subscriber = Spy(SubscriberImpl, constructorArgs: ["Fred"])
def "should send message to subscriber"() {
when:
publisher.send("hello")
then:
1 * subscriber.receive("message1") >> "ok" // subscriber is a Spy(), used as a Mock an Stub
}
def "should send message to subscriber (actually handle 'receive')"() {
when:
publisher.send("hello")
then:
1 * subscriber.receive("message1") // subscriber is a Spy(), used as a Mock, uses real 'receive' function
}
Run Code Online (Sandbox Code Playgroud)
摘要:
如果Stub()足够,请避免使用Mock().
如果可以的话,避免使用Spy(),必须这样做可能是一种气味,暗示不正确的测试或不正确的测试对象设计.
小智 12
简单来说:
模拟:你模拟了一个类型,在运行中你会得到一个对象.此模拟对象中的方法返回返回类型的默认值.
存根:您创建一个存根类,其中根据您的要求使用定义重新定义方法.例如:在实际对象方法中,您调用外部api并返回用户名和id.在存根对象方法中,您返回一些虚拟名称.
间谍:你创建一个真实的对象,然后你窥探它.现在你可以模拟一些方法,并选择不对某些方法这样做.
一个用法区别是你不能模拟方法级别对象.您可以在方法中创建默认对象,然后监视它以获得间谍对象中方法的所需行为.
归档时间: |
|
查看次数: |
41488 次 |
最近记录: |