sab*_*ari 5 mongoose mongodb node.js
模式定义
Team.js
var TeamSchema = new Schema({
// Team Name.
name: String,
lead: String,
students :type: [{
block : Number,
status : String,
student : {
type: Schema.ObjectId,
ref: 'Student'
}]
});
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Student.js
var StudentSchema = new Schema({
name: String,
rollNo : Number,
class : Number
});
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如何填充"学生"以获得输出,如下所示:
球队
{
"__v": 1,
"_id": "5252875356f64d6d28000001",
"students": [
{
"__v": 1,
"_id": "5252875a56f64d6d28000002",
block : 1,
status : joined,
"student": {
"name": Sumeeth
"rollNo" : 2
"class" : 5
}
},
{
"__v": 1,
"_id": "5252875a56f64d6d28000003",
block : 1,
status : joined,
"student": {
"name": Sabari
"rollNo" : 3
"class" : 4
}
}
],
"lead": "Ratha",
}
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这是JS我用来使用Mongoose获取文档:
Team.findOne({
_id: req.team._id
})
.populate('students')
.select('students')
.exec(function(err, team) {
console.log(team);
var options = {
path: 'students.student',
model: 'Student'
};
Student.populate(team.students,options,function(err, students) {
console.log(students);
if (err) {
console.log(students);
res.send(500, {
message: 'Unable to query the team!'
});
} else {
res.send(200, students);
}
});
});
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在我的控制台输出中,我得到以下内容:
{ _id: 53aa434858f760900b3f2246,
students
[ { block : 1
status: 'joined'
_id: 53aa436b58f760900b3f2249 },
{ block : 1
status: 'joined'
_id: 53aa436b58f760900b3f2250 }]
}
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而预期的产出是:
{ _id: 53aa434858f760900b3f2246,
students
[ { block : 1
status: 'joined'
student :{
"name": Sumeeth
"rollNo" : 2
"class" : 5
}
},
{ block : 1
status: 'joined'
student :{
"name": Sabari
"rollNo" : 3
"class" : 4
}
}
]
}
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有人请在我错的地方帮助我.我应该如何使用.populate,这样,我可以得到整个学生对象,而不仅仅是它的id.
参考: 在mongoose中填充嵌套数组
这是您想要的简化版本。
基本数据要设置,首先是“学生”:
{
"_id" : ObjectId("53aa90c83ad07196636e175f"),
"name" : "Bill",
"rollNo" : 1,
"class" : 12
},
{
"_id" : ObjectId("53aa90e93ad07196636e1761"),
"name" : "Ted",
"rollNo" : 2,
"class" : 12
}
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然后是“团队”集合:
{
"_id" : ObjectId("53aa91b63ad07196636e1762"),
"name" : "team1",
"lead" : "me",
"students" : [
{
"block" : 1,
"status" : "Y",
"student" : ObjectId("53aa90c83ad07196636e175f")
},
{
"block" : 2,
"status" : "N",
"student" : ObjectId("53aa90e93ad07196636e1761")
}
]
}
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您可以这样做:
var async = require('async'),
mongoose = require('mongoose');
Schema = mongoose.Schema;
mongoose.connect('mongodb://localhost/team');
var teamSchema = new Schema({
name: String,
lead: String,
students: [{
block: Number,
status: String,
student: {
type: Schema.ObjectId, ref: 'Student'
}
}]
});
var studentSchema = new Schema({
name: String,
rollNo: Number,
class: Number
});
var Team = mongoose.model( "Team", teamSchema );
var Student = mongoose.model( "Student", studentSchema );
Team.findById("53aa91b63ad07196636e1762")
.select('students')
.exec(function(err, team) {
console.log( team );
async.forEach(team.students, function(student,callback) {
Student.populate(
student,
{ "path": "student" },
function(err,output) {
if (err) throw err;
callback();
}
);
},function(err) {
console.log( JSON.stringify( team, undefined, 4 ) );
});
});
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它给你结果:
{
"_id": "53aa91b63ad07196636e1762",
"students": [
{
"block": 1,
"status": "Y",
"student": {
"_id": "53aa90c83ad07196636e175f",
"name": "Bill",
"rollNo": 1,
"class": 12
}
},
{
"block": 2,
"status": "N",
"student": {
"_id": "53aa90e93ad07196636e1761",
"name": "Ted",
"rollNo": 2,
"class": 12
}
}
]
}
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你确实不需要“异步”模块,但我只是“习惯”。它不会“阻塞”,因此我认为它更好。
因此,正如您所看到的,您最初的.populate()调用不会执行任何操作,因为它期望_id从数组输入中“键”出外部集合中的值,而“严格来说”并不是这样,因为“键”位于“student” ” 包含“外键”。
我确实在最近的回答中对此进行了介绍,也许并不完全针对您的情况。看来您的搜索没有找到正确的“相同答案”(尽管不完全)供您参考。
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