iOS中的词干 - 不适合单个单词

Question

我正在使用NSLinguisticTagger词干.我能够在一个句子中得到单词的词干,但是不能为单个单词得到词干.

以下是我正在使用的代码,

    NSString *stmnt = @"i waited";
    NSLinguisticTaggerOptions options = NSLinguisticTaggerOmitWhitespace | NSLinguisticTaggerOmitPunctuation | NSLinguisticTaggerJoinNames;

    NSLinguisticTagger *tagger = [[NSLinguisticTagger alloc] initWithTagSchemes:@[NSLinguisticTagSchemeLemma] options:options];
    tagger.string = stmnt;
    [tagger enumerateTagsInRange:NSMakeRange(0, [stmnt length]) scheme:NSLinguisticTagSchemeLemma options:options usingBlock:^(NSString *tag, NSRange tokenRange, NSRange sentenceRange, BOOL *stop) {
        NSString *token = [stmnt substringWithRange:tokenRange];
        NSLog(@"%@: %@", token, tag);
    }];

为此,我正确地出去了:

i: i
waited: wait

但上面的代码无法识别词干 stmnt = @"waited";

任何帮助是极大的赞赏

Answer 1

以下代码为我工作,

NSString *stmt = @"waited";
NSRange stringRange = NSMakeRange(0, stmt.length);
NSDictionary* languageMap = @{@"Latn" : @[@"en"]};
[stmt enumerateLinguisticTagsInRange:stringRange
                                       scheme:NSLinguisticTagSchemeLemma
                                      options:NSLinguisticTaggerOmitWhitespace
                                  orthography:[NSOrthography orthographyWithDominantScript:@"Latn" languageMap:languageMap]
                                   usingBlock:^(NSString *tag, NSRange tokenRange, NSRange sentenceRange, BOOL *stop) {
                                       // Log info to console for debugging purposes
                                       NSString *currentEntity = [stmt substringWithRange:tokenRange];
                                       NSLog(@"%@ is a %@, tokenRange (%d,%d)",currentEntity,tag,tokenRange.length,tokenRange.location);
                                   }];