使用换行符作为分隔符将多行字符串转换为Ruby中的数组

Question

我想把这个字符串

"P07091 MMCNEFFEG

P06870 IVGGWECEQHS

SP0A8M0 VVPVADVLQGR

P01019 VIHNESTCEQ"

进入一个看起来像红宝石的数组.

["P07091 MMCNEFFEG", "P06870 IVGGWECEQHS", "SP0A8M0 VVPVADVLQGR", "P01019 VIHNESTCEQ"]

split由于换行符,使用不会返回我想要的内容.

Answer 1

这是处理空白行的一种方法:

string.split(/\n+/)

例如,

string = "P07091 MMCNEFFEG

P06870 IVGGWECEQHS

SP0A8M0 VVPVADVLQGR




P01019 VIHNESTCEQ"

string.split(/\n+/)
  #=> ["P07091 MMCNEFFEG", "P06870 IVGGWECEQHS",
  #    "SP0A8M0 VVPVADVLQGR", "P01019 VIHNESTCEQ"]

Answer 2

我喜欢将其用作处理换行符和返回的非常通用的方法：

lines = string.split(/\n+|\r+/).reject(&:empty?)

Answer 3

string = "P07091 MMCNEFFEG

P06870 IVGGWECEQHS

SP0A8M0 VVPVADVLQGR

P01019 VIHNESTCEQ"

运用 CSV::parse

require 'csv'

CSV.parse(string).flatten
# => ["P07091 MMCNEFFEG", "P06870 IVGGWECEQHS", "SP0A8M0 VVPVADVLQGR", "P01019 VIHNESTCEQ"]

使用的另一种方式String#each_line: -

ar = []
string.each_line { |line| ar << line.strip unless line == "\n" }
ar # => ["P07091 MMCNEFFEG", "P06870 IVGGWECEQHS", "SP0A8M0 VVPVADVLQGR", "P01019 VIHNESTCEQ"]