在C语言中阅读科学记数法

Question

我正在尝试读取具有以下内容的文件:

1.0000000e + 01 2.9265380e + 03 5.0821200e + 02 4.3231640e + 01

2.0000000e + 01 1.0170240e + 04 9.2798610e + 02 4.0723180e + 01

3.0000000e + 01 2.1486260e + 04 1.1832420e + 03 1.0328000e + 01

4.0000000e + 01 3.3835080e + 04 1.1882285e + 03 -9.3307000e + 00

5.0000000e + 01 4.5250830e + 04 1.0899705e + 03 -1.0320900e + 01

6.0000000e + 01 5.5634490e + 04 9.8935650e + 02 -9.8019000e + 00

7.0000000e + 01 6.5037960e + 04 8.9134700e + 02 -9.8000000e + 00

但我似乎无法找到一种阅读科学记谱法的正确方法.这是我的代码:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    // This is the array to store the input
    double time[24], altitude[24], velocity[24], acceleration[24];
    double var1, var2, var3, var4;

    //This is the pointer declaration for opening a file
    FILE * fp = fopen("rocket.txt", "r");

    int i = 0;

    while(fscanf(fp,"%g %f %f %f", &var1, &var2, &var3, &var4) > 0){
        time[i] = var1;
        altitude[i] = var2;
        velocity[i] = var3;
        acceleration[i] = var4;
        printf("Time: %f \n", &time[i]);
        i++;
    }

    printf("Time: %f", &time[0]);

   fclose(fp);

   return(0);
}

我已经尝试了多种组合%f, %g, %d来尝试打印结果,但我永远无法做正确的事情.

如果有人能指出我正确的方向,我将非常感激.

Answer 1

您想要使用的是科学记数法的%lf输入和%e输出:

scanf("%lf", &input);
printf("%e\n", input);