使用JRE 1.5和JDK 1.6时DocumentBuilder.parse的差异

Question

最近我们最终将项目转换为Java 1.6.在执行测试时,我发现使用1.6时,不会抛出使用1.5抛出的SAXParseException.

下面是我的测试代码来演示这个问题.

import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.SchemaFactory;

import org.junit.Test;
import org.xml.sax.InputSource;
import org.xml.sax.SAXParseException;


/**
 * Test class to demonstrate the difference between JDK 1.5 to JDK 1.6.
 * 
 * Seen on Linux:
 * 
 * <pre>
 * #java version "1.6.0_18"
 * Java(TM) SE Runtime Environment (build 1.6.0_18-b07)
 * Java HotSpot(TM) Server VM (build 16.0-b13, mixed mode)
 * </pre>
 * 
 * Seen on OSX:
 * 
 * <pre>
 * java version "1.6.0_17"
 * Java(TM) SE Runtime Environment (build 1.6.0_17-b04-248-10M3025)
 * Java HotSpot(TM) 64-Bit Server VM (build 14.3-b01-101, mixed mode)
 * </pre>
 * 
 * @author dhiller (creator)
 * @author $Author$ (last editor)
 * @version $Revision$
 * @since 12.03.2010 11:32:31
 */
public class TestXMLValidation {

  /**
   * Tests the schema validation of an XML against a simple schema.
   * 
   * @throws Exception
   *           Falls ein Fehler auftritt
   * @throws junit.framework.AssertionFailedError
   *           Falls eine Unit-Test-Pruefung fehlschlaegt
   */
  @Test(expected = SAXParseException.class)
  public void testValidate() throws Exception {
    final StreamSource schema = new StreamSource( new StringReader( "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
      + "<xs:schema xmlns:xs=\"http://www.w3.org/2001/XMLSchema\" "
      + "elementFormDefault=\"qualified\" xmlns:xsd=\"undefined\">" + "<xs:element name=\"Test\"/>" + "</xs:schema>" ) );
    final String xml = "<Test42/>";
    final DocumentBuilderFactory newFactory = DocumentBuilderFactory.newInstance();
    newFactory.setSchema( SchemaFactory.newInstance( "http://www.w3.org/2001/XMLSchema" ).newSchema( schema ) );
    final DocumentBuilder documentBuilder = newFactory.newDocumentBuilder();
    documentBuilder.parse( new InputSource( new StringReader( xml ) ) );
  }

}

当使用JVM 1.5时,测试通过,在1.6上它失败并出现"Expected exception SAXParseException".

DocumentBuilderFactory.setSchema(Schema)方法的Javadoc 说:

当错误被验证发现,解析器负责向他们报告给用户指定的ErrorHandler(或者如果错误处理程序没有设置,忽略他们或扔),就像由解析器自己发现的任何其他错误.换句话说,如果设置了用户指定的ErrorHandler,它必须接收这些错误,如果没有,则必须根据特定于实现的默认错误处理规则来处理它们.

DocumentBuilder.parse(InputSource)方法的Javadoc 说:

BTW:我尝试通过setErrorHandler设置错误处理程序,但仍然没有异常.

现在我的问题:

什么已更改为1.6,阻止架构验证抛出SAXParseException？它与我试图解析的模式或xml有关吗？

更新:

以下代码适用于1.5和1.6,因为我一直希望:

  @Test(expected = SAXParseException.class)
  public void testValidate() throws Exception {
    final StreamSource schema = new StreamSource( new StringReader( "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
      + "<xs:schema xmlns:xs=\"http://www.w3.org/2001/XMLSchema\" "
      + "elementFormDefault=\"qualified\" xmlns:xsd=\"undefined\">" + "<xs:element name=\"Test\"/>" + "</xs:schema>" ) );
    final String xml = "<Test42/>";
    final DocumentBuilderFactory newFactory = DocumentBuilderFactory.newInstance();
    final Schema newSchema = SchemaFactory.newInstance( "http://www.w3.org/2001/XMLSchema" ).newSchema( schema );
    newFactory.setSchema( newSchema );
    final Validator newValidator = newSchema.newValidator();
    final Source is = new StreamSource( new StringReader( xml ) );
    try {
      newValidator.validate( ( Source ) is );
    }
    catch ( Exception e ) {
      e.printStackTrace();
      throw e;
    }
    final DocumentBuilder documentBuilder = newFactory.newDocumentBuilder();
    documentBuilder.parse( new InputSource( new StringReader( xml ) ) );
  }

解决方案似乎是显式使用从Schema实例创建的Validator实例.我在这里找到了解决方案

我还不确定那是为什么......

Answer 1

显然，不符合模式的文档只值得默认错误处理程序对 stderr 进行温和的谴责。我的解决方案是用更严格的错误处理程序替换默认的错误处理程序：

// builder is my DocumentBuilder
builder.setErrorHandler(new ErrorHandler() {
    @Override
    public void error(SAXParseException arg0) throws SAXException {
        throw arg0;             
    }

    @Override
    public void fatalError(SAXParseException arg0) throws SAXException {
        throw arg0;                 
    }

    @Override
    public void warning(SAXParseException arg0) throws SAXException {
        throw arg0;                 
    }
});