05:00:00 - 28:59:59时间格式

Question

我有数据集,time.start从5:00:00到28:59:59(即01.01.2013 28:00:00实际上是02.01.2013 04:00:00).日期是%d.%m.%Y格式.

      Date Time.start   
01.01.2013   22:13:07
01.01.2013   22:52:23
01.01.2013   23:34:06
01.01.2013   23:44:25
01.01.2013   27:18:48
01.01.2013   28:41:04

我想将其转换为普通日期格式.

dates$date <- paste(dates$Date,dates$Time.start, sep = " ")
dates$date <- as.POSIXct(strptime(dates$date, "%m.%d.%Y %H:%M:%S"))

但显然我有NA时间> 23:59:59

我应该如何修改我的代码？

Answer 1

例如,将时间添加为日期的秒数:

df <- read.table(header=T, text="      Date Time.start   
01.01.2013   22:13:07
01.01.2013   22:52:23
01.01.2013   23:34:06
01.01.2013   23:44:25
01.01.2013   27:18:48
01.01.2013   28:41:04", stringsAsFactors=FALSE)

as.POSIXct(df$Date, format="%d.%m.%Y") +
  sapply(strsplit(df$Time.start, ":"), function(t) {
    t <- as.integer(t)
    t[3] + t[2] * 60 + t[1] * 60 * 60
  })

# [1] "2013-01-01 22:13:07 CET" "2013-01-01 22:52:23 CET" "2013-01-01 23:34:06 CET"
# [4] "2013-01-01 23:44:25 CET" "2013-01-02 03:18:48 CET" "2013-01-02 04:41:04 CET"

Answer 2

只需修改lukeAs解决方案:

with(df, as.POSIXct(Date, format="%d.%m.%Y")+
 colSums(t(read.table(text=Time.start, sep=":",header=F))*c(3600,60,1)))
[1] "2013-01-01 22:13:07 EST" "2013-01-01 22:52:23 EST" 
[3] "2013-01-01 23:34:06 EST" "2013-01-01 23:44:25 EST"
[5] "2013-01-02 03:18:48 EST" "2013-01-02 04:41:04 EST"