为什么以下代码的输出是25448？

Question

当我尝试运行此代码时,它提供以下输出:

c
99
25448
4636795

我想知道编译器如何生成最后两个输出？

#include<iostream>
#include<stdio.h>
using namespace std;
int main()
{
    char ch='c';

    printf("%c\n",ch);
    printf("%d\n",ch);
    printf("%d\n",'ch');
    printf("%d","ch");

    return 0;
}

Answer 1

printf("%c",ch);       - print normal character
printf("%d\n",ch);     - print ascii value of character
printf("%d\n",'ch');   - multi-character literal
printf("%d","ch");     - print value of pointer to string "ch"

关于'ch'

0x6368对于'c',25448是和63是十六进制,对于'h',68是十六进制