JPA认为我正在删除一个分离的对象

Question

我有一个DAO,我曾经使用JPA加载和保存我的域对象.我终于设法使交易工作正常,现在我又遇到了另一个问题.

在我的测试用例中,我调用我的DAO来加载具有给定id的域对象,检查它是否已加载,然后调用相同的DAO来删除刚刚加载的对象.当我这样做时,我得到以下内容:

java.lang.IllegalArgumentException: Removing a detached instance mil.navy.ndms.conops.common.model.impl.jpa.Group#10
 at org.hibernate.ejb.event.EJB3DeleteEventListener.performDetachedEntityDeletionCheck(EJB3DeleteEventListener.java:45)
 at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:108)
 at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:74)
 at org.hibernate.impl.SessionImpl.fireDelete(SessionImpl.java:794)
 at org.hibernate.impl.SessionImpl.delete(SessionImpl.java:772)
 at org.hibernate.ejb.AbstractEntityManagerImpl.remove(AbstractEntityManagerImpl.java:253)
 at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
 at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:48)
 at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37)
 at java.lang.reflect.Method.invoke(Method.java:600)
 at org.springframework.orm.jpa.SharedEntityManagerCreator$SharedEntityManagerInvocationHandler.invoke(SharedEntityManagerCreator.java:180)
 at $Proxy27.remove(Unknown Source)
 at mil.navy.ndms.conops.common.dao.impl.jpa.GroupDao.delete(GroupDao.java:499)
 at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
 at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:48)
 at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37)
 at java.lang.reflect.Method.invoke(Method.java:600)
 at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:304)
 at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:182)
 at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:149)
 at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106)
 at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171)
 at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204)
 at $Proxy28.delete(Unknown Source)
 at mil.navy.ndms.conops.common.dao.impl.jpa.GroupDaoTest.testGroupDaoSave(GroupDaoTest.java:89)
 at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
 at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:48)
 at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37)
 at java.lang.reflect.Method.invoke(Method.java:600)
 at junit.framework.TestCase.runTest(TestCase.java:164)
 at junit.framework.TestCase.runBare(TestCase.java:130)
 at junit.framework.TestResult$1.protect(TestResult.java:106)
 at junit.framework.TestResult.runProtected(TestResult.java:124)
 at junit.framework.TestResult.run(TestResult.java:109)
 at junit.framework.TestCase.run(TestCase.java:120)
 at junit.framework.TestSuite.runTest(TestSuite.java:230)
 at junit.framework.TestSuite.run(TestSuite.java:225)
 at org.eclipse.jdt.internal.junit.runner.junit3.JUnit3TestReference.run(JUnit3TestReference.java:130)
 at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
 at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:460)
 at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:673)
 at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:386)
 at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:196)

现在假设我正在使用相同的DAO实例,并且我没有更改EntityManagers(除非Spring不这样做而不让我知道),这怎么可能是一个分离的对象？

我的DAO代码如下所示:

public class GenericJPADao<INTFC extends IAddressable, VO extends BaseAddressable> implements IWebDao, IDao<INTFC>, IDaoUtil<INTFC>
{
    private static Logger logger = Logger.getLogger (GenericJPADao.class);

    protected Class<?> voClass;

    @PersistenceContext(unitName = "CONOPS_PU")
    protected EntityManagerFactory emf;

    @PersistenceContext(unitName = "CONOPS_PU")
    protected EntityManager em;

    public GenericJPADao()
    {
        super ( );

        ParameterizedType genericSuperclass = 
                        (ParameterizedType) getClass ( ).getGenericSuperclass ( );
        this.voClass = (Class<?>) genericSuperclass.getActualTypeArguments ( )[1];
    }


    ...


    public void delete (INTFC modelObj, EntityManager em)
    {
        em.remove (modelObj);
    }

    @SuppressWarnings("unchecked")
    public INTFC findById (Long id)
    {
        return ((INTFC) em.find (voClass, id));
    }
}

测试用例代码如下:

IGroup loadedGroup = dao.findById (group.getId ( ));
assertNotNull (loadedGroup);
assertEquals (group.getId ( ), loadedGroup.getId ( ));

dao.delete (loadedGroup); // - This generates the above exception

loadedGroup = dao.findById (group.getId ( ));
assertNull(loadedGroup);

谁能告诉我这里我做错了什么？

Answer 1

我怀疑你正在运行的事务外的代码,以便您find和delete操作发生在一个单独的持久化上下文和find实际返回一个超脱实例(所以JPA是正确的,你ARE删除分离的对象).

在事务中包装您的查找/删除序列.

更新:在7.3.1章节的摘录下面.事务持久化上下文:

如果EntityManager在活动事务之外使用事务持久性上下文模型,则每个方法调用都会创建新的持久性上下文,执行方法操作并结束持久性上下文.例如,考虑在EntityManager.find事务之外使用该方法.该EntityManager会创建一个临时的持久化上下文,执行查找操作,最终持久化上下文,将剥离结果对象返还给您.具有相同id的第二个调用将返回第二个分离的对象.

Answer 2

public void remove(Object obj){
    em.remove(em.merge(obj));
}

上面的代码类似于zawhtut提出的代码

Answer 3

+1来Pascal Thivent的帖子,只是一个跟进.

    @Transactional
    public void remove(long purchaseId){
        Purchase attached = jpaTemplate.find(Purchase.class,purchaseId);
        jpaTemplate.remove(attached);
    }

Answer 4

通过使用em.getReference()而不是获取实例em.find().

例如,尝试:

em.remove(em.getReference(INTFC.class, id));