调用IronPython函数时CodeContext的相关性

Question

我正在用C#调用IronPython函数.似乎在定义上,此函数捕获其原始范围.当我稍后在没有显式范围的情况下调用它时,它仍然可以访问该原始范围的值.即使我更改范围值,它也会正确读取新值.看看这个例子:

using IronPython.Hosting;
using IronPython.Runtime;
using IronPython.Runtime.Operations;
using Microsoft.Scripting;
using Microsoft.Scripting.Hosting;

namespace IronPythonFuncTest {
    class Program {
        static void Main() {
            ScriptEngine scriptEngine = Python.CreateEngine();

            // Create scope with a global value for the script to use
            ScriptScope scriptScope = scriptEngine.CreateScope();
            scriptScope.SetVariable("someGlobalValue", 10);

            // Execute script defining function foo(x)
            string script = "def foo(): print(someGlobalValue)";
            ScriptSource scriptSource = scriptEngine.
                CreateScriptSourceFromString(script, SourceCodeKind.Statements);
            scriptSource.Execute(scriptScope);

            // Extract foo from the scope
            PythonFunction foo = scriptScope.GetVariable<PythonFunction>("foo");

            // Change someGlobalValue
            scriptScope.SetVariable("someGlobalValue", 42);

            // Call foo. This prints 42, not 10 (or nothing).
            PythonCalls.Call(foo);
        }
    }
}

现在我想知道:大多数PythonCalls.Call()期望一个CodeContext对象的重载(如果我理解正确,主要代表一个范围).如果我在不传递代码上下文的情况下调用上面的IronPython函数,我会丢失一些东西吗？鉴于该函数显然在创建时捕获了其原始范围,因此传递额外的代码上下文似乎没有任何意义.是否存在使我有所作为的情况？

Answer 1

你为什么打电话foo过来PythonCall.Call？尝试这样做：scriptScope.Host.ScriptEngine.Operations.InvokeMember(CLASS-Instance, METHOD-Name, ARGUMENTS);Ironpython 将CodeContext自行正确处理。您可以在此处找到示例实现：DlrClass/InvokeMember。

据我所知，这CodeContext不仅仅是范围，只需看一下定义即可：

/// <summary>
/// Captures and flows the state of executing code from the generated 
/// Python code into the IronPython runtime.
/// </summary>    
[DebuggerTypeProxy(typeof(CodeContext.DebugProxy)), DebuggerDisplay("module: {ModuleName}", Type="module")]
public sealed class CodeContext { // ... }

希望这可以帮助！