Laravel JSON响应返回受保护的数据

Question

return Response::json(array('status' => 'Group not found'));

返回受保护的数据 这是JSON:

{"status":"Group not found"}

以下代码

//$jsonData - the data returned above

var_dump($jsonData);

返回:

object(Illuminate\Http\JsonResponse)#320(10){["jsonOptions":protected] => int(0)["data":protected] => string(28)"{"status":"未找到组"}"["callback":protected] => NULL ["encodingOptions":protected] => int(15)["headers"] => object(Symfony\Component\HttpFoundation\ResponseHeaderBag)#317(5){[ "computedCacheControl":protected] => array(1){["no-cache"] => bool(true)} ["cookies":protected] => array(0){} ["headerNames":protected] = > array(3){["cache-control"] => string(13)"Cache-Control"["content-type"] => string(12)"Content-Type"["date"] => string (4)"Date"} ["headers":protected] => array(3){["cache-control"] => array(1){[0] => string(8)"no-cache"} ["content-type"] => array(1){[0] => string(16)"application/json"} ["date"] => array(1){[0] => string(29) "星期二,2014年6月17日19:03:33 GMT"}} ["cacheControl":protected] => array(0){}} ["content":protected] => string(28)"{"status": "未找到组"}"["版本":protected] => string(3)"1.0"["statusCode":protected] => int(200)["s tatusText":protected] => string(2)"OK"["charset":protected] => NULL}

看看["data":protected]=> string(28) "{"status":"Group not found"}".由于某种原因,数据受到保护,并且在解码JSON时不会出现.我如何"取消保护"它(公开发布)？

Answer 1

我不认为这是你的问题.

如果你看一下继承树:

\Symfony\Component\HttpFoundation\Response
    \Symfony\Component\HttpFoundation\JsonResponse
        \Illuminate\Http\JsonResponse

祖先Response类具有:

public function __toString()
{
    ...
    return ... . $this->getContent();
}

所以我们遵循:

public function getContent()
{
    return $this->content;
}

您的数据存储在成员中是可以的,protected $content因为当JsonResponse对象强制转换为字符串时,PHP使用该__toString()方法的返回值作为该对象的字符串表示形式.