假设我有桌子#Foo:
Id Color
-- ----
1 Red
2 Green
3 Blue
4 NULL
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和表#Bar:
Value
-----
1
2.5
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我想创建表Result使用简单的语句来获取:
Id Color Value
-- ---- -----
1 Red 1
2 Green 2.5
3 Blue NULL
4 NULL NULL
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到目前为止我发明的是:
WITH cte1
AS
(
SELECT [Id], [Color], ROW_NUMBER() OVER (ORDER BY [Id]) AS 'No'
FROM #Foo
),
cte2
AS
(
SELECT [Value], ROW_NUMBER() OVER (ORDER BY [Value]) AS 'No'
FROM #Bar
)
SELECT [Id], [Color], [Value]
FROM cte1 c1
FULL OUTER JOIN cte2 c2 ON c1.[No] = c2.[No]
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您是否知道在T-SQL中进行ZIP JOIN的更快或更标准的方法?
您可以摆脱the CTE或使您的query shorter
子查询是这样的
select Id,Color,Value from
(
SELECT [Id], [Color], ROW_NUMBER() OVER (ORDER BY [Id]) AS 'No'
FROM #Foo
)x full outer join
(
SELECT [Value], ROW_NUMBER() OVER (ORDER BY [Value]) AS 'No'
FROM #Bar
)y
on x.No=y.No
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