TypeError:使用%s时格式字符串的参数不足

Question

这是我的代码

import sys
name = input("Enter your name:")
last_name = input("Enter your last name:")
gender = input("Enter your gender:")
age = input("Enter your age:")
print ("So your name is %s, your last name is %s, you are %s and you are %s years old" % name, last_name, gender, age)

我搜索了这个话题,但我不明白.

Answer 1

您需要在括号中放置字符串格式的参数:

print (... % (name, last_name, gender, age))

否则,Python将仅name作为字符串格式的参数,其余作为函数的参数print.

但是请注意,%这些天使用字符串格式化操作是不受欢迎的.现代方法是使用str.format:

print ("So your name is {}, your last name is {}, you are {} and you are {} years old".format(name, last_name, gender, age))

Answer 2

你需要一组括号:

>>> '%s %s' % 'a', 'b'  # what you have
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: not enough arguments for format string
>>>
>>>
>>> '%s %s' % ('a', 'b')  # correct solution
'a b'

'%s %s' % 'a', 'b'被评估为('%s %s' % 'a'), 'b','%s %s' % 'a'因为参数少于格式说明符,所以会产生错误.

print("So your name is %s, your last name is %s, you are %s and you are %s years old" % (name, last_name, gender, age))