Ric*_*ich 1 google-maps bing-maps google-maps-api-3
目的:
计算给定点到最近道路的距离.我需要确定一个点是否落在道路上.要做到这一点,我想看到从点到最近的道路的距离.因此,距离0意味着该点实际上在道路上.
附加信息:
我不受Google地图的限制.如果Bing地图或其他地图服务提供此功能,那么该服务也是一个考虑因素.
题:
您是否知道使用Google Maps API v3计算从给定点到最近道路的距离?如果不是,您是否知道我可以实现目标的另一种方法或服务?
问题解决了.这是演示:http: //jsfiddle.net/63sWv/
var marker = null;
var roadMarker = null;
var geocoder = new google.maps.Geocoder();
var map;
var directionsService = new google.maps.DirectionsService();
$(document).ready(function(){
var latlng = new google.maps.LatLng(54.97430382488778, -1.611546277999878);
var mapOptions = {
zoom: 22,
center: latlng
};
map = new google.maps.Map(document.getElementById('map'), mapOptions);
google.maps.event.addListener(map, 'click', function(event) {
placeMarkers(event);
});
});
function placeMarkers(e) {
var markerImage = "https://chart.googleapis.com/chart?chst=d_map_pin_icon&chld=home|FFFF00";
var roadMarkerImage ="https://chart.googleapis.com/chart?chst=d_map_xpin_letter&chld=pin||FF0000|000000";
if(marker !== null){
marker.setMap(null);
}
marker = new google.maps.Marker({
position: e.latLng,
map: map,
icon: markerImage
});
var request = {
origin:e.latLng,
destination:e.latLng,
travelMode: google.maps.DirectionsTravelMode.DRIVING
};
directionsService.route(request, function(response, status) {
if (status == google.maps.DirectionsStatus.OK) {
if(roadMarker !== null){
roadMarker.setMap(null);
}
roadMarker = new google.maps.Marker({
position: response.routes[0].legs[0].start_location,
map: map,
icon: roadMarkerImage
});
var distance = getDistance(request.origin,
response.routes[0].legs[0].steps[0].end_point);
$(".output .distance").html(distance);
}
});
}
var rad = function(x) {
return x * Math.PI / 180;
};
var getDistance = function(p1, p2) {
//trim up to 5 decimal places because it is at that point where the difference
p1.lat = parseFloat(p1.lat().toFixed(5));
p1.lng = parseFloat(p1.lng().toFixed(5));
p2.lat = parseFloat(p2.lat().toFixed(5));
p2.lng = parseFloat(p2.lng().toFixed(5));
var R = 6378137; // Earth’s mean radius in meter
var dLat = rad(p2.lat - p1.lat);
var dLong = rad(p2.lng - p1.lng);
var a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.cos(rad(p1.lat)) * Math.cos(rad(p2.lat)) * Math.sin(dLong / 2) * Math.sin(dLong / 2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
var d = R * c;
return d; // returns the distance in meter
};
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