Jam*_*mes 6 java hibernate timeout jpa entitymanager
我目前正从EntityManager查询中获取连接超时错误.是否可以为这些设置超时?
persistence.xml中
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="CallPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>call.structure.Task</class>
<class>call.structure.Installation</class>
<class>call.structure.Contents</class>
<class>call.structure.Recipient</class>
<class>call.structure.CallTask</class>
<class>call.structure.SmsTask</class>
<class>call.structure.EmailTask</class>
<class>call.security.User</class>
<class>call.structure.content.Content</class>
<class>call.structure.content.RecordContent</class>
<class>call.structure.content.WaitContent</class>
<class>call.structure.content.TextContent</class>
<class>call.structure.content.VariableContent</class>
<class>call.structure.content.SoundContent</class>
<class>call.structure.content.SubjectContent</class>
<class>call.structure.content.FileContent</class>
<class>call.structure.Bounce</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@127.0.0.1:1521:TEST"/>
<property name="javax.persistence.jdbc.password" value="userpassword"/>
<property name="javax.persistence.jdbc.driver" value="oracle.jdbc.OracleDriver"/>
<property name="javax.persistence.jdbc.user" value="username"/>
</properties>
</persistence-unit>
</persistence>
Run Code Online (Sandbox Code Playgroud)
代码在我的线程的run函数中超时:
private class TaskDB extends Thread {
private final long WAITING_TIME = 20000L;
@Override
public void run() {
Set<SmsTask> remove = SMSManager.this.getRemoveTask();
Set<SmsTask> normal = SMSManager.this.getNormalTask();
try {
while(true){
EntityManager em = DB.getEM(); //Calls EntityManagerFactory.createEntityManager()
em.getTransaction().begin();
Set<SmsTask> normalClone = new HashSet<SmsTask>(normal);
// Abort task in futur.
List<SmsTask> taskToRemove = new ArrayList<SmsTask>();
if (!remove.isEmpty()) {
String queryString = "SELECT t FROM SmsTask t WHERE t.id IN :remove ";
if (!normalClone.isEmpty())
queryString += "AND t.id NOT IN :normal ";
Query query = em.createQuery(queryString);
query.setParameter("remove", Utils.taskToIdList(remove));
if (!normalClone.isEmpty())
query.setParameter("normal", Utils.taskToIdList(normalClone));
taskToRemove = (List<SmsTask>) query.getResultList();
for (SmsTask task : taskToRemove) {
removedTask.add(task);
remove.remove(task);
}
}
String queryString = "SELECT t FROM SmsTask t WHERE (t.scheduleTime IS NULL OR t.scheduleTime < :dateNow) AND t.status = co.dium.call.structure.Task.StatusTask.NOT_START ";
if (!taskToRemove.isEmpty())
queryString += "AND t.id NOT IN :toRemove ";
Query query = em.createQuery(queryString);
query.setParameter("dateNow", Utils.obtainUniversalTime());
if (!taskToRemove.isEmpty())
query.setParameter("toRemove", Utils.taskToIdList(taskToRemove));
List<SmsTask> taskResults = (List<SmsTask>) query.getResultList();
em.getTransaction().commit();
for (SmsTask task : taskResults)
addTask(task);
SMSManager.TaskRemove.sleep(WAITING_TIME);
}
} catch (InterruptedException ex) {
Logger.getLogger(SMSManager.class.getName()).log(Level.SEVERE, null, ex);
}
System.out.println("Thread interrompu !");
Thread.currentThread().interrupt();
}
}
Run Code Online (Sandbox Code Playgroud)
我得到的超时错误:
org.clipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLRecoverableException: I/O error: Socket read timed out
Error Code: 17002
Call: [....sql query...]
[...]
at org.eclipse.persistence.internal.EJBQueryImpl.getResultList(EJBQueryImpl.java:742)
at call.manager.sms.SMSManager$TaskDB.run(SMSManager.java:367)
Caused by: java.sql.SQLRecoverableException: I/O Error: Scoket read timed out
[...]
Run Code Online (Sandbox Code Playgroud)
Mik*_*unu 19
是的,有javax.persistence.query.timeout.根据JPA 2.0规范支持此查询提示是可选的:
便携式应用程序不应该依赖这个提示.根据使用的持久性提供程序和数据库,可能会也可能不会显示提示.
对于所有查询,可以将缺省值(以毫秒为单位)设置为persistence.xml:
<property name="javax.persistence.query.timeout" value="1000"/>
Run Code Online (Sandbox Code Playgroud)
通过Persistence创建EntityManagerFactory时也可以给出相同的属性.createEntityManagerFactory.
它也可以为每个查询覆盖/设置:
query.setHint("javax.persistence.query.timeout", 2000);
Run Code Online (Sandbox Code Playgroud)
可以通过NamedQuery中的属性提示获得相同的功能.
有两种方法可以使用 Hibernate 设置查询超时期限。
如果您本地引导 Hibernate 或者将 JPA 解包java.persistence.Query为其org.hibernate.query.Query等效项,那么您可以使用以下setTimeout方法:
List<Post> posts = entityManager
.createQuery(
"select p " +
"from Post p " +
"where lower(p.title) like lower(:titlePattern)", Post.class)
.setParameter("titlePattern", "%Hibernate%")
.unwrap(org.hibernate.query.Query.class)
.setTimeout(1)
.getResultList();
Run Code Online (Sandbox Code Playgroud)
请注意,该
setTimeout方法采用一个int参数来指定超时值(以秒为单位) 。
您还可以使用 JPA 查询提示,如以下示例所示:
List<Post> posts = entityManager
.createQuery(
"select p " +
"from Post p " +
"where lower(p.title) like lower(:titlePattern)", Post.class)
.setParameter("titlePattern", "%Hibernate%")
.setHint("javax.persistence.query.timeout", 50)
.getResultList();
Run Code Online (Sandbox Code Playgroud)
请注意,查询提示采用以毫秒
javax.persistence.query.timeout为单位的超时值。
您还可以使用org.hibernate.timeout查询提示:
List<Post> posts = entityManager
.createQuery(
"select p " +
"from Post p " +
"where lower(p.title) like lower(:titlePattern)", Post.class)
.setParameter("titlePattern", "%Hibernate%")
.setHint("org.hibernate.timeout", 1)
.getResultList();
Run Code Online (Sandbox Code Playgroud)
请注意,查询提示采用以秒
org.hibernate.timeout为单位的超时值。
| 归档时间: |
|
| 查看次数: |
24365 次 |
| 最近记录: |