Mic*_*ael 3 java apache ms-word apache-poi
我目前正在尝试处理上一篇名为" 替换Apache POI XWPF中的文本"的文章中提到的代码.
我已经尝试了以下它可以工作,但我不知道我是否遗漏了任何东西.当我运行代码时,文本不会被替换,而是添加到搜索结尾.例如,我创建了一个基本的word文档,并输入了文本"test".在下面的代码中,当我运行它时,我最终得到带有文本"testDOG"的新文档.
我不得不将原始代码从String text = r.getText(0)更改为String text = r.toString(),因为我在运行代码时不断收到NullError.
import java.io.*;
import org.apache.poi.openxml4j.opc.OPCPackage;
import org.apache.poi.xwpf.extractor.XWPFWordExtractor;
import org.apache.poi.xwpf.usermodel.XWPFDocument;
import org.apache.poi.xwpf.usermodel.XWPFParagraph;
import org.apache.poi.xwpf.usermodel.XWPFRun;
public class testPOI {
public static void main(String[] args) throws Exception{
String filepath = "F:\\MASTER_DOC.docx";
String outpath = "F:\\Test.docx";
XWPFDocument doc = new XWPFDocument(OPCPackage.open(filepath));
for (XWPFParagraph p : doc.getParagraphs()){
for (XWPFRun r : p.getRuns()){
String text = r.toString();
if(text.contains("test")) {
text = text.replace("test", "DOG");
r.setText(text);
}
}
}
doc.write(new FileOutputStream(outpath));
}
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编辑:感谢大家的帮助.我浏览了一下,在Apache POI中找到了替换表列值的解决方案
此方法在段落中替换搜索字符串,并且能够使用跨越多个Run的字符串.
private long replaceInParagraphs(Map<String, String> replacements, List<XWPFParagraph> xwpfParagraphs) {
long count = 0;
for (XWPFParagraph paragraph : xwpfParagraphs) {
List<XWPFRun> runs = paragraph.getRuns();
for (Map.Entry<String, String> replPair : replacements.entrySet()) {
String find = replPair.getKey();
String repl = replPair.getValue();
TextSegement found = paragraph.searchText(find, new PositionInParagraph());
if ( found != null ) {
count++;
if ( found.getBeginRun() == found.getEndRun() ) {
// whole search string is in one Run
XWPFRun run = runs.get(found.getBeginRun());
String runText = run.getText(run.getTextPosition());
String replaced = runText.replace(find, repl);
run.setText(replaced, 0);
} else {
// The search string spans over more than one Run
// Put the Strings together
StringBuilder b = new StringBuilder();
for (int runPos = found.getBeginRun(); runPos <= found.getEndRun(); runPos++) {
XWPFRun run = runs.get(runPos);
b.append(run.getText(run.getTextPosition()));
}
String connectedRuns = b.toString();
String replaced = connectedRuns.replace(find, repl);
// The first Run receives the replaced String of all connected Runs
XWPFRun partOne = runs.get(found.getBeginRun());
partOne.setText(replaced, 0);
// Removing the text in the other Runs.
for (int runPos = found.getBeginRun()+1; runPos <= found.getEndRun(); runPos++) {
XWPFRun partNext = runs.get(runPos);
partNext.setText("", 0);
}
}
}
}
}
return count;
}
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你的逻辑不太对。您需要先整理运行中的所有文本,然后进行替换。您还需要删除该段落的所有运行,并在找到“test”匹配时添加新的单个运行。
试试这个:
public class testPOI {
public static void main(String[] args) throws Exception{
String filepath = "F:\\MASTER_DOC.docx";
String outpath = "F:\\Test.docx";
XWPFDocument doc = new XWPFDocument(new FileInputStream(filepath));
for (XWPFParagraph p : doc.getParagraphs()){
int numberOfRuns = p.getRuns().size();
// Collate text of all runs
StringBuilder sb = new StringBuilder();
for (XWPFRun r : p.getRuns()){
int pos = r.getTextPosition();
if(r.getText(pos) != null) {
sb.append(r.getText(pos));
}
}
// Continue if there is text and contains "test"
if(sb.length() > 0 && sb.toString().contains("test")) {
// Remove all existing runs
for(int i = 0; i < numberOfRuns; i++) {
p.removeRun(i);
}
String text = sb.toString().replace("test", "DOG");
// Add new run with updated text
XWPFRun run = p.createRun();
run.setText(text);
p.addRun(run);
}
}
doc.write(new FileOutputStream(outpath));
}
}
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