Shr*_*yas 219 sql sql-server sql-server-2005
我需要在SQL服务器上编写一个查询来获取特定表中的列列表,其关联的数据类型及其长度以及它们是否为空.我设法做了这么多.但是现在我还需要针对列进入同一个表 - 如果它是主键,则为TRUE.我该怎么做呢 ?
这是输出应该是这样的:
TRUE
请帮我!
mar*_*c_s 452
要避免某些列的重复行,请使用user_type_id而不是system_type_id.
SELECT
c.name 'Column Name',
t.Name 'Data type',
c.max_length 'Max Length',
c.precision ,
c.scale ,
c.is_nullable,
ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM
sys.columns c
INNER JOIN
sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN
sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN
sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
c.object_id = OBJECT_ID('YourTableName')
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只需替换YourTableName为您的实际表名 - 适用于SQL Server 2005及更高版本.
dec*_*led 90
存储过程sp_columns返回详细的表信息.
exec sp_columns MyTable
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Aja*_*dex 64
您可以使用查询:
select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH,
NUMERIC_PRECISION, DATETIME_PRECISION,
IS_NULLABLE
from INFORMATION_SCHEMA.COLUMNS
where TABLE_NAME='TableName'
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获取除Pk信息之外的所有元数据.
小智 16
在SQL 2012中,您可以使用:
EXEC sp_describe_first_result_set N'SELECT * FROM [TableName]'
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这将为您提供列名称及其属性.
小智 13
试试这个:
select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE
from INFORMATION_SCHEMA.COLUMNS IC
where TABLE_NAME = 'tablename' and COLUMN_NAME = 'columnname'
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为确保获得正确的长度,您需要将unicode类型视为特殊情况.见下面的代码.
有关详细信息,请参阅:https://msdn.microsoft.com/en-us/library/ms176106.aspx
SELECT
c.name 'Column Name',
t.name,
t.name +
CASE WHEN t.name IN ('char', 'varchar','nchar','nvarchar') THEN '('+
CASE WHEN c.max_length=-1 THEN 'MAX'
ELSE CONVERT(VARCHAR(4),
CASE WHEN t.name IN ('nchar','nvarchar')
THEN c.max_length/2 ELSE c.max_length END )
END +')'
WHEN t.name IN ('decimal','numeric')
THEN '('+ CONVERT(VARCHAR(4),c.precision)+','
+ CONVERT(VARCHAR(4),c.Scale)+')'
ELSE '' END
as "DDL name",
c.max_length 'Max Length in Bytes',
c.precision ,
c.scale ,
c.is_nullable,
ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM
sys.columns c
INNER JOIN
sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN
sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN
sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
c.object_id = OBJECT_ID('YourTableName')
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将另一个答案扔进戒指,这将为您提供这些列以及更多内容:
SELECT col.TABLE_CATALOG AS [Database]
, col.TABLE_SCHEMA AS Owner
, col.TABLE_NAME AS TableName
, col.COLUMN_NAME AS ColumnName
, col.ORDINAL_POSITION AS OrdinalPosition
, col.COLUMN_DEFAULT AS DefaultSetting
, col.DATA_TYPE AS DataType
, col.CHARACTER_MAXIMUM_LENGTH AS MaxLength
, col.DATETIME_PRECISION AS DatePrecision
, CAST(CASE col.IS_NULLABLE
WHEN 'NO' THEN 0
ELSE 1
END AS bit)AS IsNullable
, COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsIdentity')AS IsIdentity
, COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsComputed')AS IsComputed
, CAST(ISNULL(pk.is_primary_key, 0)AS bit)AS IsPrimaryKey
FROM INFORMATION_SCHEMA.COLUMNS AS col
LEFT JOIN(SELECT SCHEMA_NAME(o.schema_id)AS TABLE_SCHEMA
, o.name AS TABLE_NAME
, c.name AS COLUMN_NAME
, i.is_primary_key
FROM sys.indexes AS i JOIN sys.index_columns AS ic ON i.object_id = ic.object_id
AND i.index_id = ic.index_id
JOIN sys.objects AS o ON i.object_id = o.object_id
LEFT JOIN sys.columns AS c ON ic.object_id = c.object_id
AND c.column_id = ic.column_id
WHERE i.is_primary_key = 1)AS pk ON col.TABLE_NAME = pk.TABLE_NAME
AND col.TABLE_SCHEMA = pk.TABLE_SCHEMA
AND col.COLUMN_NAME = pk.COLUMN_NAME
WHERE col.TABLE_NAME = 'YourTableName'
AND col.TABLE_SCHEMA = 'dbo'
ORDER BY col.TABLE_NAME, col.ORDINAL_POSITION;
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SELECT COLUMN_NAME, IS_NULLABLE, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM information_schema.columns WHERE table_name = '<name_of_table_or_view>'
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SELECT *在上面的语句中运行以查看 information_schema.columns 返回什么。
这个问题之前已经回答过 - /sf/answers/788791951/
扩展Alex的答案,你可以这样做以获得PK约束
Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH, C.NUMERIC_PRECISION, C.IS_NULLABLE, TC.CONSTRAINT_NAME
From INFORMATION_SCHEMA.COLUMNS As C
Left Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
On TC.TABLE_SCHEMA = C.TABLE_SCHEMA
And TC.TABLE_NAME = C.TABLE_NAME
And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
Where C.TABLE_NAME = 'Table'
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我一定错过了你想要一个标志来确定给定的列是否是PK的一部分而不是PK约束的名称.为此您将使用:
Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH
, C.NUMERIC_PRECISION, C.NUMERIC_SCALE
, C.IS_NULLABLE
, Case When Z.CONSTRAINT_NAME Is Null Then 0 Else 1 End As IsPartOfPrimaryKey
From INFORMATION_SCHEMA.COLUMNS As C
Outer Apply (
Select CCU.CONSTRAINT_NAME
From INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
Join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE As CCU
On CCU.CONSTRAINT_NAME = TC.CONSTRAINT_NAME
Where TC.TABLE_SCHEMA = C.TABLE_SCHEMA
And TC.TABLE_NAME = C.TABLE_NAME
And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
And CCU.COLUMN_NAME = C.COLUMN_NAME
) As Z
Where C.TABLE_NAME = 'Table'
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