SQL Server查询以获取表中的列列表以及Data types,NOT NULL和PRIMARY KEY约束

Shr*_*yas 219 sql sql-server sql-server-2005

我需要在SQL服务器上编写一个查询来获取特定表中的列列表,其关联的数据类型及其长度以及它们是否为空.我设法做了这么多.但是现在我还需要针对列进入同一个表 - 如果它是主键,则为TRUE.我该怎么做呢 ?

这是输出应该是这样的:

TRUE

请帮我!

mar*_*c_s 452

要避免某些列的重复行,请使用user_type_id而不是system_type_id.

SELECT 
    c.name 'Column Name',
    t.Name 'Data type',
    c.max_length 'Max Length',
    c.precision ,
    c.scale ,
    c.is_nullable,
    ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM    
    sys.columns c
INNER JOIN 
    sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN 
    sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN 
    sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
    c.object_id = OBJECT_ID('YourTableName')
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只需替换YourTableName为您的实际表名 - 适用于SQL Server 2005及更高版本.

  • 这些长度**没有错** - 它确实给出字节长度 - 这是字节长度的最大长度...如果你想计算空间等,那就是你想得到的长度.... (14认同)
  • 如果您有多个索引涉及同一列,则此查询将返回重复的列。要修复它,请用以下内容替换最后两个联接:`LEFT OUTER JOIN sys.index_columns ic LEFT OUTER JOIN sys.indexes i ON ic.object_id = i.object_id和ic.index_id = i.index_id ON ic.object_id = c .object_id AND ic.column_id = c.column_id AND i.is_primary_key = 1` (7认同)
  • 哇这太棒了..也适用于sql server 2000 ..谢谢 (3认同)
  • 这为nvarchar等类型的列提供了错误的长度.它给出的字节长度是列类型长度的两倍. (2认同)
  • 适合我的SQL Server 2012 :) (2认同)
  • 在哪里c.object_id = OBJECT_ID('YourTableName')....我需要在哪里c.object_id = OBJECT_ID('MySchema.MyTableName')然后一切正常。 (2认同)
  • 该查询为我节省了大量时间,因为我的表有60多个列。这也完美地工作。 (2认同)

dec*_*led 90

存储过程sp_columns返回详细的表信息.

exec sp_columns MyTable
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  • 如果使用它,请注意“MyTable”实际上只是表名称,而不是模式。要过滤到架构,请将其添加为第二个参数:`exec sp_columns 'MyTable', 'MySchema'` (3认同)
  • 真正.但它不会再给pk信息:( (2认同)
  • exec sp_pkeys exec sp_fkeys (2认同)
  • 简短的查询,但做得很好. (2认同)

Aja*_*dex 64

您可以使用查询:

select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH, 
       NUMERIC_PRECISION, DATETIME_PRECISION, 
       IS_NULLABLE 
from INFORMATION_SCHEMA.COLUMNS
where TABLE_NAME='TableName'
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获取除Pk信息之外的所有元数据.

  • 我做到了:)但我也需要PK:| (2认同)

小智 16

在SQL 2012中,您可以使用:

EXEC sp_describe_first_result_set N'SELECT * FROM [TableName]'
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这将为您提供列名称及其属性.


小智 13

试试这个:

select COLUMN_NAME, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE 
from INFORMATION_SCHEMA.COLUMNS IC
where TABLE_NAME = 'tablename' and COLUMN_NAME = 'columnname'
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  • 您的答案与Ajadex发布的答案有何不同?两个答案都不会返回主键信息. (2认同)

Mic*_*per 9

为确保获得正确的长度,您需要将unicode类型视为特殊情况.见下面的代码.

有关详细信息,请参阅:https://msdn.microsoft.com/en-us/library/ms176106.aspx

SELECT 
   c.name 'Column Name',
   t.name,
   t.name +
   CASE WHEN t.name IN ('char', 'varchar','nchar','nvarchar') THEN '('+

             CASE WHEN c.max_length=-1 THEN 'MAX'

                  ELSE CONVERT(VARCHAR(4),

                               CASE WHEN t.name IN ('nchar','nvarchar')

                               THEN  c.max_length/2 ELSE c.max_length END )

                  END +')'

          WHEN t.name IN ('decimal','numeric')

                  THEN '('+ CONVERT(VARCHAR(4),c.precision)+','

                          + CONVERT(VARCHAR(4),c.Scale)+')'

                  ELSE '' END

   as "DDL name",
   c.max_length 'Max Length in Bytes',
   c.precision ,
   c.scale ,
   c.is_nullable,
   ISNULL(i.is_primary_key, 0) 'Primary Key'
FROM    
   sys.columns c
INNER JOIN 
   sys.types t ON c.user_type_id = t.user_type_id
LEFT OUTER JOIN 
   sys.index_columns ic ON ic.object_id = c.object_id AND ic.column_id = c.column_id
LEFT OUTER JOIN 
   sys.indexes i ON ic.object_id = i.object_id AND ic.index_id = i.index_id
WHERE
   c.object_id = OBJECT_ID('YourTableName')
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  • DDL 名称对于创建表的动态 SQL 非常有用!谢谢!! (2认同)

Jus*_*lle 6

将另一个答案扔进戒指,这将为您提供这些列以及更多内容:

SELECT col.TABLE_CATALOG AS [Database]
     , col.TABLE_SCHEMA AS Owner
     , col.TABLE_NAME AS TableName
     , col.COLUMN_NAME AS ColumnName
     , col.ORDINAL_POSITION AS OrdinalPosition
     , col.COLUMN_DEFAULT AS DefaultSetting
     , col.DATA_TYPE AS DataType
     , col.CHARACTER_MAXIMUM_LENGTH AS MaxLength
     , col.DATETIME_PRECISION AS DatePrecision
     , CAST(CASE col.IS_NULLABLE
                WHEN 'NO' THEN 0
                ELSE 1
            END AS bit)AS IsNullable
     , COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsIdentity')AS IsIdentity
     , COLUMNPROPERTY(OBJECT_ID('[' + col.TABLE_SCHEMA + '].[' + col.TABLE_NAME + ']'), col.COLUMN_NAME, 'IsComputed')AS IsComputed
     , CAST(ISNULL(pk.is_primary_key, 0)AS bit)AS IsPrimaryKey
  FROM INFORMATION_SCHEMA.COLUMNS AS col
       LEFT JOIN(SELECT SCHEMA_NAME(o.schema_id)AS TABLE_SCHEMA
                      , o.name AS TABLE_NAME
                      , c.name AS COLUMN_NAME
                      , i.is_primary_key
                   FROM sys.indexes AS i JOIN sys.index_columns AS ic ON i.object_id = ic.object_id
                                                                     AND i.index_id = ic.index_id
                                         JOIN sys.objects AS o ON i.object_id = o.object_id
                                         LEFT JOIN sys.columns AS c ON ic.object_id = c.object_id
                                                                   AND c.column_id = ic.column_id
                  WHERE i.is_primary_key = 1)AS pk ON col.TABLE_NAME = pk.TABLE_NAME
                                                  AND col.TABLE_SCHEMA = pk.TABLE_SCHEMA
                                                  AND col.COLUMN_NAME = pk.COLUMN_NAME
 WHERE col.TABLE_NAME = 'YourTableName'
   AND col.TABLE_SCHEMA = 'dbo'
 ORDER BY col.TABLE_NAME, col.ORDINAL_POSITION;
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Mar*_*dor 6

SELECT COLUMN_NAME, IS_NULLABLE, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM information_schema.columns WHERE table_name = '<name_of_table_or_view>'
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SELECT *在上面的语句中运行以查看 information_schema.columns 返回什么。

这个问题之前已经回答过 - /sf/answers/788791951/


Mar*_*que 6

我有点惊讶没人提到

sp_help 'mytable'
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Tho*_*mas 5

扩展Alex的答案,你可以这样做以获得PK约束

Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH, C.NUMERIC_PRECISION, C.IS_NULLABLE, TC.CONSTRAINT_NAME
From INFORMATION_SCHEMA.COLUMNS As C
    Left Join INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
      On TC.TABLE_SCHEMA = C.TABLE_SCHEMA
          And TC.TABLE_NAME = C.TABLE_NAME
          And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
Where C.TABLE_NAME = 'Table'
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我一定错过了你想要一个标志来确定给定的列是否是PK的一部分而不是PK约束的名称.为此您将使用:

Select C.COLUMN_NAME, C.DATA_TYPE, C.CHARACTER_MAXIMUM_LENGTH
    , C.NUMERIC_PRECISION, C.NUMERIC_SCALE
    , C.IS_NULLABLE
    , Case When Z.CONSTRAINT_NAME Is Null Then 0 Else 1 End As IsPartOfPrimaryKey
From INFORMATION_SCHEMA.COLUMNS As C
    Outer Apply (
                Select CCU.CONSTRAINT_NAME
                From INFORMATION_SCHEMA.TABLE_CONSTRAINTS As TC
                    Join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE As CCU
                        On CCU.CONSTRAINT_NAME = TC.CONSTRAINT_NAME
                Where TC.TABLE_SCHEMA = C.TABLE_SCHEMA
                    And TC.TABLE_NAME = C.TABLE_NAME
                    And TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
                    And CCU.COLUMN_NAME = C.COLUMN_NAME
                ) As Z
Where C.TABLE_NAME = 'Table'
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小智 5

在查询编辑器中单击表名称,选择名称,然后按Alt + F1,它将带入表的所有信息。