Chr*_*her 5 java sql spring hibernate spring-data
我在CrudRepository中设计查询时遇到了一些麻烦.
我有两个实体,CourseOffering和Department(仅显示相关代码):
CourseOffering.java:
public class CourseOffering implements Serializable
{
private Department department;
@ManyToOne(fetch = FetchType.LAZY, optional = true)
@JoinColumn(name = "DepartmentId", nullable = true)
@JsonProperty
public Department getDepartment()
{
return this.department;
}
public void setDepartment(Department department)
{
this.department = department;
}
}
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Department.java:
public class Department implements Serializable
{
private Set<CourseOffering> courses;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "department")
public Set<CourseOffering> getCourses() {
return this.courses;
}
public void setCourses(Set<CourseOffering> courses) {
this.courses = courses;
}
}
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和有问题的CrudRepository:
CourseOfferingRepository.java:
import java.util.List;
import edu.ucdavis.dss.dw.entities.CourseOffering;
import org.springframework.data.repository.CrudRepository;
public interface CourseOfferingRepository extends CrudRepository<CourseOffering, Long>
{
CourseOffering getOneByTermIdAndNumberAndDepartmentId(long termId, String number,
long departmentId);
List<CourseOffering> findByDepartmentCode(String deptCode);
//List<CourseOffering> findAllByDepartmentCode(String deptCodes);
List<CourseOffering> findByTermCode(String termCode);
}
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CourseOfferingRepository中未注释掉的三个函数按预期工作.我想让第四个工作.
我想做的是能够返回所有CourseOfferings,其中部门代码是许多部门代码之一.请注意,CourseOffering表本身只包含一个department_id整数,该整数引用Department表中的ID,其中存储了实际的deptCode.
我如何才能将注释掉的CrudRepository函数正常工作?或换句话说,如何制作复数版本的"List findByDepartmentCode(String deptCode);"?
提前感谢您提供的任何建议.
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