Alf*_*nto 3 openlayers leaflet
这是一个如何在ol2 http://jsfiddle.net/4S5Ke/166/中编写一个函数来执行此操作的示例.以下是一些代码:
function createGeodesicPolygon(origin, radius, sides, rotation, projection) {
if (projection.getCode() !== "EPSG:4326") {
origin.transform(projection, new OpenLayers.Projection("EPSG:4326"));
}
var latlon = new OpenLayers.LonLat(origin.x, origin.y);
var angle;
var new_lonlat, geom_point;
var points = [];
for (var i = 0; i < sides; i++) {
angle = (i * 360 / sides) + rotation;
new_lonlat = OpenLayers.Util.destinationVincenty(latlon, angle, radius);
new_lonlat.transform(new OpenLayers.Projection("EPSG:4326"), projection);
geom_point = new OpenLayers.Geometry.Point(new_lonlat.lon, new_lonlat.lat);
points.push(geom_point);
}
var ring = new OpenLayers.Geometry.LinearRing(points);
return new OpenLayers.Geometry.Polygon([ring]);
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}
什么是OpenLayers.Util.destinationVincenty和OpenLayers.Geometry.LinearRing等函数的传单?知道了,我想我可以使用传单重写函数.救命??
Alf*_*nto 11
嗯..我最后做的是重写几个OpenLayers 2函数,以便他们使用Leaflet工作.一个函数在半径周围创建一个正多边形.它看起来像这样:
function createGeodesicPolygon(origin, radius, sides, rotation, projection) {
var latlon = origin; //leaflet equivalent
var angle;
var new_lonlat, geom_point;
var points = [];
for (var i = 0; i < sides; i++) {
angle = (i * 360 / sides) + rotation;
new_lonlat = destinationVincenty(latlon, angle, radius);
geom_point = L.latLng(new_lonlat.lng, new_lonlat.lat);
points.push(geom_point);
}
return points;
}
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}
现在为一些触发.首先,我们设置一些常量:
L.Util.VincentyConstants = {
a: 6378137,
b: 6356752.3142,
f: 1/298.257223563
};
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然后我们重写OpenLayers.Util.destinationVincenty函数http://dev.openlayers.org/docs/files/OpenLayers/Util-js.html#Util.destinationVincenty以使用Leaflet.
参数:lonlat - (具有.lat,.lng属性的任何对象)起点.brng - {Float}轴承(度).dist - {Float}地面距离(米).
返回:{L.latLng}目标点.
很多三角函数.不要害怕.我们只需改变几行(感谢John B.这个函数看起来像传单一样.
function destinationVincenty(lonlat, brng, dist) { //rewritten to work with leaflet
var u = L.Util;
var ct = u.VincentyConstants;
var a = ct.a, b = ct.b, f = ct.f;
var lon1 = lonlat.lng;
var lat1 = lonlat.lat;
var s = dist;
var pi = Math.PI;
var alpha1 = brng * pi/180 ; //converts brng degrees to radius
var sinAlpha1 = Math.sin(alpha1);
var cosAlpha1 = Math.cos(alpha1);
var tanU1 = (1-f) * Math.tan( lat1 * pi/180 /* converts lat1 degrees to radius */ );
var cosU1 = 1 / Math.sqrt((1 + tanU1*tanU1)), sinU1 = tanU1*cosU1;
var sigma1 = Math.atan2(tanU1, cosAlpha1);
var sinAlpha = cosU1 * sinAlpha1;
var cosSqAlpha = 1 - sinAlpha*sinAlpha;
var uSq = cosSqAlpha * (a*a - b*b) / (b*b);
var A = 1 + uSq/16384*(4096+uSq*(-768+uSq*(320-175*uSq)));
var B = uSq/1024 * (256+uSq*(-128+uSq*(74-47*uSq)));
var sigma = s / (b*A), sigmaP = 2*Math.PI;
while (Math.abs(sigma-sigmaP) > 1e-12) {
var cos2SigmaM = Math.cos(2*sigma1 + sigma);
var sinSigma = Math.sin(sigma);
var cosSigma = Math.cos(sigma);
var deltaSigma = B*sinSigma*(cos2SigmaM+B/4*(cosSigma*(-1+2*cos2SigmaM*cos2SigmaM)-
B/6*cos2SigmaM*(-3+4*sinSigma*sinSigma)*(-3+4*cos2SigmaM*cos2SigmaM)));
sigmaP = sigma;
sigma = s / (b*A) + deltaSigma;
}
var tmp = sinU1*sinSigma - cosU1*cosSigma*cosAlpha1;
var lat2 = Math.atan2(sinU1*cosSigma + cosU1*sinSigma*cosAlpha1,
(1-f)*Math.sqrt(sinAlpha*sinAlpha + tmp*tmp));
var lambda = Math.atan2(sinSigma*sinAlpha1, cosU1*cosSigma - sinU1*sinSigma*cosAlpha1);
var C = f/16*cosSqAlpha*(4+f*(4-3*cosSqAlpha));
var lam = lambda - (1-C) * f * sinAlpha *
(sigma + C*sinSigma*(cos2SigmaM+C*cosSigma*(-1+2*cos2SigmaM*cos2SigmaM)));
var revAz = Math.atan2(sinAlpha, -tmp); // final bearing
var lamFunc = lon1 + (lam * 180/pi); //converts lam radius to degrees
var lat2a = lat2 * 180/pi; //converts lat2a radius to degrees
return L.latLng(lamFunc, lat2a);
}
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由于我使用Leaflet.Draw来创建圆圈,我这样调用它:
map.on('draw:created', function (e) {
var type = e.layerType,
layer = e.layer;
if (type === 'circle') {
var origin = layer.getLatLng(); //center of drawn circle
var radius = layer.getRadius(); //radius of drawn circle
var projection = L.CRS.EPSG4326;
var polys = createGeodesicPolygon(origin, radius, 60, 0, projection); //these are the points that make up the circle
var polygon = []; // store the geometry
for (var i = 0; i < polys.length; i++) {
var geometry = [polys[i].lat, polys[i].lng];
polygon.push(geometry);
}
var polyCircle = L.polygon(polygon).addTo(map); //convert geometry to a leaflet polygon and add it to the map
} else {....}
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而已!希望能帮助到你.