Kum*_*mar 11 python arguments keyword hyphen
我有一个关键字参数函数:
def f1(**kw):
for key,val in kw.iteritems():
print "key=%s val=%s" % (key,val)
f1(Attr1 = "Val1", Attr2 = "Val2") # works fine.
f1(Attr1-SubAttr = "Val1", Attr2 = "Val2") # complains about keyword being an expression.
f1("Attr1-SubAttr" = "Val1", Attr2 = "Val2") # doesn't work either.
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如何使用连字符传递关键字?我无法控制这些关键字,因为我正在从现有的旧数据库中解析这些关键字.
谢谢!-kumar
Mar*_*ers 22
关键字参数必须是有效的Python标识符 ; 这些不允许-为减法保留.
您可以使用**kwargsvariable关键字参数语法传递任意字符串:
f1(**{"Attr1-SubAttr": "Val1", "Attr2": "Val2"})
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