Swift:确定iOS屏幕大小

Question

我想使用Swift代码在我的应用中正确定位项目,无论屏幕尺寸是多少.例如,如果我想要一个按钮占屏幕宽度的75%,我可以做一些类似于(screenWidth * .75)按钮宽度的事情.我发现这可以通过Objective-C来确定

CGFloat screenWidth = screenSize.width;
CGFloat screenHeight = screenSize.height;

不幸的是,我不确定如何将其转换为Swift.有没有人有想法？

谢谢!

Answer 1

在Swift 3.0中

let screenSize = UIScreen.main.bounds
let screenWidth = screenSize.width
let screenHeight = screenSize.height

在较旧的swift:做这样的事情:

let screenSize: CGRect = UIScreen.mainScreen().bounds

然后你可以像这样访问宽度和高度:

let screenWidth = screenSize.width
let screenHeight = screenSize.height

如果你想要75%的屏幕宽度,你可以去:

let screenWidth = screenSize.width * 0.75

Swift 4.0

// Screen width.
public var screenWidth: CGFloat {
    return UIScreen.main.bounds.width
}

// Screen height.
public var screenHeight: CGFloat {
    return UIScreen.main.bounds.height
}