Android捕获未处理的异常并显示对话框

Question

我想在没有任何第三方库的应用程序中处理未处理的异常.

所以我写了一个代码.

活动:

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    Thread.setDefaultUncaughtExceptionHandler(new ReportHelper(this));
    throw new NullPointerException();
}

我的崩溃处理程序

import android.app.AlertDialog;
import android.content.Context;
import android.content.DialogInterface;
import android.os.Handler;
import android.os.Looper;
import android.os.Message;
import android.os.MessageQueue;
import android.widget.Toast;

/**
 * Created by S-Shustikov on 08.06.14.
 */
public class ReportHelper implements Thread.UncaughtExceptionHandler {
    private final AlertDialog dialog;
    private       Context     context;

    public ReportHelper(Context context) {
        this.context = context;
        AlertDialog.Builder builder = new AlertDialog.Builder(context);
        builder.setMessage("Application was stopped...")
                .setPositiveButton("Report to developer about this problem.", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {

                    }
                })
                .setNegativeButton("Exit", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {
                        // Not worked!
                        dialog.dismiss();
                        System.exit(0);
                        android.os.Process.killProcess(android.os.Process.myPid());

                    }
                });

        dialog = builder.create();
    }

    @Override
    public void uncaughtException(Thread thread, Throwable ex) {
        showToastInThread("OOPS!");
    }

    public void showToastInThread(final String str){
        new Thread() {
            @Override
            public void run() {
                Looper.prepare();
                Toast.makeText(context, "OOPS! Application crashed", Toast.LENGTH_SHORT).show();
                if(!dialog.isShowing())
                    dialog.show();
                Looper.loop();

            }
        }.start();
    }
}

当我启动应用程序时,你看到我扔了NullPointerException.Toast在我的处理逻辑显示,并显示对话框.但!对话框点击无法正确处理.我的意思是onClick方法中的逻辑没有奏效.问题是什么以及如何解决这个问题？

Answer 1

在我的例子中,我移动AlertDialog.Builder了线程运行函数,如下所示:

public void showToastInThread(final String str){
    new Thread() {
        @Override
        public void run() {
            Looper.prepare();

            AlertDialog.Builder builder = new AlertDialog.Builder(context);
            builder.setMessage("Application was stopped...")
            .setPositiveButton("Report to developer about this problem.", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id) {

                }
            })
            .setNegativeButton("Exit", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id) {
                    // Not worked!
                    dialog.dismiss();
                    System.exit(0);
                    android.os.Process.killProcess(android.os.Process.myPid());

                }
            });

            dialog = builder.create();


            Toast.makeText(context, "OOPS! Application crashed", Toast.LENGTH_SHORT).show();
            if(!dialog.isShowing())
                dialog.show();
            Looper.loop();

        }
    }.start();
}

一切都很完美.

希望这对你有所帮助.