use*_*455 2 java regex youtube-data-api
我正在使用 Youtube data api v3 获取视频信息,如标题、观看次数和持续时间。持续时间值对我来说是新的,因为ISO8601 date
我需要将其转换为可读格式,如 hh:mm:ss。持续时间可以有以下不同的值:
我可以使用Joda Time 库来解析该值并计算以秒为单位的持续时间,但该库的大小为 500kb,这会增加我不想要的应用程序的大小。
看看这段代码:
private static HashMap<String, String> regexMap = new HashMap<>();
private static String regex2two = "(?<=[^\\d])(\\d)(?=[^\\d])";
private static String two = "0$1";
public static void main(String[] args) {
regexMap.put("PT(\\d\\d)S", "00:$1");
regexMap.put("PT(\\d\\d)M", "$1:00");
regexMap.put("PT(\\d\\d)H", "$1:00:00");
regexMap.put("PT(\\d\\d)M(\\d\\d)S", "$1:$2");
regexMap.put("PT(\\d\\d)H(\\d\\d)S", "$1:00:$2");
regexMap.put("PT(\\d\\d)H(\\d\\d)M", "$1:$2:00");
regexMap.put("PT(\\d\\d)H(\\d\\d)M(\\d\\d)S", "$1:$2:$3");
String[] dates = { "PT1S", "PT1M", "PT1H", "PT1M1S", "PT1H1S", "PT1H1M", "PT1H1M1S", "PT10H1M13S", "PT10H1S", "PT1M11S" };
for (String date : dates) {
String d = date.replaceAll(regex2two, two);
String regex = getRegex(d);
if (regex == null) {
System.out.println(d + ": invalid");
continue;
}
String newDate = d.replaceAll(regex, regexMap.get(regex));
System.out.println(date + " : " +newDate);
}
}
private static String getRegex(String date) {
for (String r : regexMap.keySet())
if (Pattern.matches(r, date))
return r;
return null;
}
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用于regex2two
将前导零添加0
到 1 位数字。你可以试试这个演示。
在regexMap
我存储了所有 7 个案例和适当的正则表达式替换。