在Swift准备Segue

Question

我正面临错误消息:

"UIStoryboardSegue does not have a member named 'identifier'"

这是导致错误的代码

if (segue.identifier == "Load View") {
    // pass data to next view
}

在Obj-C上使用这样很好:

if ([segue.identifier isEqualToString:@"Load View"]) {
   // pass data to next view
}

我究竟做错了什么？

Answer 1

这似乎是由于UITableViewController子类模板中的问题.它附带了一个版本的prepareForSegue方法,需要你解开segue.

用以下内容替换当前prepareForSegue功能:

override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject!) {
    if (segue.identifier == "Load View") {
        // pass data to next view
    }
}

这个版本隐含地打开参数,所以你应该没事.

Answer 2

Swift 4,Swift 3

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "MySegueId" {
        if let nextViewController = segue.destination as? NextViewController {
                nextViewController.valueOfxyz = "XYZ" //Or pass any values
                nextViewController.valueOf123 = 123
        }
    }
}

Answer 3

我认为问题是你必须使用!解开标识符

我有

override func prepareForSegue(segue: UIStoryboardSegue?, sender: AnyObject?) {
        if segue!.identifier == "Details" {
            let viewController:ViewController = segue!.destinationViewController as ViewController
            let indexPath = self.tableView.indexPathForSelectedRow()
            viewController.pinCode = self.exams[indexPath.row]

        }

    }

我的理解是没有!你只是得到一个真或假的价值

Answer 4

对于Swift 2.3,swift3和swift4:

在didSelectRowAtindexPath创建一个执行Segue

对于Ex:

   self.performSegue(withIdentifier: "uiView", sender: self)

之后创建一个prepareforSegue函数来捕获Destination segue并传递值:

例如:

  override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

       if segue.identifier == "uiView"{

        let destView = segue.destination as! WebViewController
        let indexpath = self.newsTableView.indexPathForSelectedRow
        let indexurl = tableDatalist[(indexpath?.row)!].link
        destView.UrlRec = indexurl

        //let url =

    }
    }

您需要在Destination ViewController中创建名为UrlRec的变量

Answer 5

Swift 1.2

    override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!) {
            if (segue.identifier == "ShowDeal") {

                if let viewController: DealLandingViewController = segue.destinationViewController as? DealLandingViewController {
                    viewController.dealEntry = deal
                }

            }
     }

Answer 6

为 Swift 4.2 和 Swift 5 中的 Segue 做准备。

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if (segue.identifier == "OrderVC") {
        // pass data to next view
        let viewController = segue.destination as? MyOrderDetailsVC
        viewController!.OrderData = self.MyorderArray[selectedIndex]


    }
}

如何在特定事件上调用 segue（如按钮单击等）：

performSegue(withIdentifier: "OrderVC", sender: self)