Raj*_*071 182 string concat string-concatenation swift
如何在Swift中连接字符串?
在Objective-C我们不喜欢
NSString *string = @"Swift";
NSString *resultStr = [string stringByAppendingString:@" is a new Programming Language"];
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要么
NSString *resultStr=[NSString stringWithFormat:@"%@ is a new Programming Language",string];
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但是我想用Swift语言做这件事.
Fog*_*ter 321
您可以通过多种方式连接字符串:
let a = "Hello"
let b = "World"
let first = a + ", " + b
let second = "\(a), \(b)"
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你也可以这样做:
var c = "Hello"
c += ", World"
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我相信还有更多方法.
一点描述
let创造一个常数.(有点像NSString).设置后,您无法更改其值.您仍然可以将其添加到其他内容并创建新变量.
var创建一个变量.(有点像NSMutableString)所以你可以改变它的价值.但是Stack Overflow已经多次回答了这个问题(参见let和var之间的区别).
注意
在现实中let,并var有很大的不同,从NSString和NSMutableString,但它可以帮助类比.
Arb*_*tur 60
您可以通过以下方式添加字符串:
str += ""str = str + ""str = str + str2str = "" + ""str = "\(variable)"str = str + "\(variable)"我想我把它们都命名了.
yoe*_*ven 29
var language = "Swift"
var resultStr = "\(language) is a new programming language"
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CW0*_*007 13
这也可以:
var string = "swift"
var resultStr = string + " is a new Programming Language"
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Jit*_*dra 11
\这用于将一个字符串附加到另一个字符串.
var first = "Hi"
var combineStr = "\(first) Start develop app for swift"
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您也可以尝试: - +关键字.
var first = "Hi"
var combineStr = "+(first) Start develop app for swift"
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试试这个代码.
Bag*_*ndt 10
let the_string = "Swift"
let resultString = "\(the_string) is a new Programming Language"
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非常简单:
let StringA = "Hello"
let StringB = "World"
let ResultString = "\(StringA)\(StringB)"
println("Concatenated result = \(ResultString)")
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您现在可以在Swift中使用stringByAppendingString.
var string = "Swift"
var resultString = string.stringByAppendingString(" is new Programming Language")
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XCode不接受使用普通字符串添加的可选字符串.我写了这个扩展来解决这个问题:
extension String {
mutating func addString(str: String) {
self = self + str
}
}
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然后你可以这样称呼它:
var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1.addString(str2)
println(str1) //hi my name is
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但是你现在也可以这样做:
var str1: String?
var str1 = "hi"
var str2 = " my name is"
str1! += str2
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您可以使用appendingAPI 来实现它。这将返回一个通过将给定字符串附加到接收者而形成的新字符串。
API 详细信息:此处
使用:
var text = "Hello"
text = text.appending(" Namaste")
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结果:
Hello
Hello Namaste
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