FOS UserBundle无法登录

Question

关于我的UserBundle,我又回到了另一个问题:通过Symfony2安装和配置FOS捆绑包时,一切都很完美,它甚至让我创建了2个正确插入我的数据库的用户.

但是,每次我尝试登录这些帐户时,都会出现以下错误

Warning: Erroneous data format for unserializing 'VillaPrivee\UserBundle\Entity\User' in /Users/Vianney/Projets/VillaPrivee/vendor/doctrine/orm/lib/Doctrine/ORM/Mapping/ClassMetadataInfo.php line 869

这就是869行所指的:

/**
     * Creates a new instance of the mapped class, without invoking the constructor.
     *
     * @return object
     */
    public function newInstance()
    {
        if ($this->_prototype === null) {
            $this->_prototype = unserialize(sprintf('O:%d:"%s":0:{}', strlen($this->name), $this->name));
        }

        return clone $this->_prototype;
    }

这是我的用户实体:

namespace VillaPrivee\UserBundle\Entity;

use FOS\UserBundle\Model\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity
 * @ORM\Table(name="fos_user")
 */
class User extends BaseUser
{
    /**
     * @ORM\Id
     * @ORM\Column(type="integer")
     * @ORM\GeneratedValue(strategy="AUTO")
     */
    protected $id;

    public function __construct()
    {
        parent::__construct();
        // your own logic
    }
}

不知道我做错了什么,因为我只是按照一步一步的文档安装了整件事...感谢各位帮忙

Answer 1

如果您使用的是PHP版本5.4.29或5.5.13

在:"/ vendor/doctrine/orm/lib/Doctrine/ORM/Mapping/ClassMetadataInfo.php "中找到函数"newInstance"(在第827行附近)并按照下面的步骤进行编辑,直到Fix通过doctrine合并为止.

public function newInstance()
{
    if ($this->_prototype === null) {
        // $this->_prototype = unserialize(sprintf('O:%d:"%s":0:{}', strlen($this->name), $this->name));
        if (PHP_VERSION_ID === 50429 || PHP_VERSION_ID === 50513) {
            $this->_prototype = $this->reflClass->newInstanceWithoutConstructor();
        } else {
            $this->_prototype = unserialize(sprintf('O:%d:"%s":0:{}', strlen($this->name), $this->name));
        }
    }
    return clone $this->_prototype;
}

@Benji:thx的提示:https://github.com/symfony/symfony/issues/11056

Answer 2

回答我自己的问题,我找到了一个解决方法,感谢这个家伙:

http://www.doctrine-project.org/jira/browse/DDC-3120

在谈到解释时,他比我好得多,但这就是我现在所拥有的,它就像一个魅力!:)

{
        if ($this->_prototype === null) {
            $this->_prototype = @unserialize(sprintf('O:%d:"%s":0:{}', strlen($this->name), $this->name));
            if ($this->_prototype === false) {
                $this->_prototype = @unserialize(sprintf('C:%d:"%s":0:{}', strlen($this->name), $this->name));
            }
        }

        return clone $this->_prototype;
    }