navigator.geolocation.watchPosition - 频率

Question

navigator.geolocation.watchPosition - 频率

我尝试了这段代码：

<!DOCTYPE html>
<html>
  <head>
    <title>Location Location Location</title>

    <script type="text/javascript" charset="utf-8">

    var watchID = null;

    // PhoneGap is ready
    //
    function f() {
        // Update every 1 ms seconds
        var options = {enableHighAccuracy: true,timeout: 5000,maximumAge: 0,desiredAccuracy: 0, frequency: 1 };
        watchID = navigator.geolocation.watchPosition(onSuccess, onError, options);
    }

    // onSuccess Geolocation
    //
    function onSuccess(position) {
        var xmlhttp;
        if (window.XMLHttpRequest){// code for IE7+, Firefox, Chrome, Opera, Safari
            xmlhttp=new XMLHttpRequest();
        }else{// code for IE6, IE5
            xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
        }       
        var str = 'Latitude: '  + position.coords.latitude      + '<br>' +
                  'Longitude: ' + position.coords.longitude     + '<br>' +
                  'Timestamp: ' + position.timestamp     + '<br>' ;
        var url = "load.php";
        var params = "data="+str;
        xmlhttp.open("GET", url+"?"+params, true);
        document.body.innerHTML += str;
        document.writeln("line 33");
        xmlhttp.send();
        //document.writeln("send");
        //document.writeln(str);
    }

    // clear the watch that was started earlier
    // 
    function clearWatch() {
        if (watchID != null) {
            navigator.geolocation.clearWatch(watchID);
            watchID = null;
        }
    }

    // onError Callback receives a PositionError object
    //
    function onError(error) {
      alert('code: '    + error.code    + '\n' +
            'message: ' + error.message + '\n');
    }

    </script>
  </head>
  <body>
    <p id="geolocation">Watching geolocation...</p>
    <button onclick="f();"> Watch</button>     
  </body>
</html>

Run Code Online (Sandbox Code Playgroud)

你可以看到我添加了

var options = {......, frequency: 1 };
watchID = navigator.geolocation.watchPosition(onSuccess, onError, options);

Run Code Online (Sandbox Code Playgroud)

但当且仅当我进入选项卡并退出并输入 agin 时，我才会得到新结果。

我能做些什么？

Answer 1

Ram*_*der 5

该规范没有提及频率选项，这表明该参数被忽略。W3C 地理定位规范

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