loo*_*sta 17 block nsurlconnection swift
有人知道处理程序(块)如何在swift中工作吗?我正在尝试运行此代码,但我找不到完成正确语法的任何文档.
let url:NSURL = NSURL(string:"some url")
let request:NSURLRequest = NSURLRequest(URL:url)
let queue:NSOperationQueue = NSOperationQueue()
NSURLConnection.sendAsynchronousRequest(request:request, queue:queue, completionHandler handler:((NSURLResponse!, NSData!, NSError!) -> Void)!)
Tom*_*art 41
像这样:
NSURLConnection.sendAsynchronousRequest(request, queue: queue, completionHandler:{ response, data, error in /* Your code */ })
或者更详细的变体.
NSURLConnection.sendAsynchronousRequest(request, queue: queue, completionHandler:{ (response: NSURLResponse!, data: NSData!, error: NSError!) -> Void in
    /* Your code */
})
| 归档时间: | 
 | 
| 查看次数: | 23316 次 | 
| 最近记录: |