我在php中做一个Web服务来将数据编码为json.我的PHP代码是:
function getProgramDay($day)
{
global $DDBB_SERVER, $DDBB_USER, $DDBB_PASSWORD, $DDBB;
$sql = "SELECT program.id, programa.name FROM `mybd` WHERE program.day = '" . $day . "'";
$con = mysqli_connect($DDBB_SERVER, $DDBB_USER, $DDBB_PASSWORD, $DDBB);
if (!$con) {
die('Error de Conexión (' . mysqli_connect_errno() . '): ' . mysqli_connect_error());
}
if (!mysqli_set_charset($con, "utf8")) {
die("Error loading character set utf8:" . mysqli_error($con));
}
$result = mysqli_query($con, $sql);
$res = array();
// Prepare data
while ($row = mysqli_fetch_assoc($result)) {
$res[] = $row;
}
// Free resultset
mysqli_free_result($result);
// Close connection
mysqli_close($con);
// Return data
return $res;
}
Run Code Online (Sandbox Code Playgroud)
而这个函数在json中的结果是:
[{"id":"1","nombre":"Hello"}]
Run Code Online (Sandbox Code Playgroud)
我希望结果如下:
{"results":[{"id":"1","nombre":"Hello"}]}
Run Code Online (Sandbox Code Playgroud)
我怎样才能做到这一点?我试过但不行:
return "{'results':" .$res . "}";
Run Code Online (Sandbox Code Playgroud)
非常感谢 :-)
return json_encode(array("results"=>$res));
Run Code Online (Sandbox Code Playgroud)
如评论中所述,如果要返回数组并在调用代码中创建json,请执行以下操作:
return array("results"=>$res);
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
81 次 |
| 最近记录: |