关闭/隐藏活动状态onStop上的Android软键盘

Question

我的布局中有一个EditText和一个Button.在编辑字段中写入并单击此按钮后 go back my fragment,我想隐藏虚拟键盘.我认为有一个简单的,但我尝试了某种方式,它不起作用:

该代码显示了如何Button工作:

private void onButtonClicked(){
    getActivity().getSupportFragmentManager().popBackStack();
}

某些解决方案的代码,但这无济于事.这个代码我用,hideSoftInputFromWindow但是当我调用'EditText.getWindowToken()'时,它不会隐藏软键盘(我也将0值更改为InputMethodManager.HIDE_IMPLICIT_ONLY或InputMethodManager.HIDE_NOT_ALWAYS并且它不起作用):

EditText myEditText = (EditText) findViewById(R.id.myEditText);  
InputMethodManager imm = (InputMethodManager)getSystemService(
      Context.INPUT_METHOD_SERVICE);
imm.hideSoftInputFromWindow(myEditText.getWindowToken(), 0);

使用此代码,在此应用程序的另一个屏幕中,它可以工作.这个屏幕是一个活动所以我认为问题是片段的问题.

我的片段代码:

public class ChangeEmailFragment extends BaseFragment {
    private TextView mTxtCurrentEmail;
    private EditText mEdtNewEmail;
    private EditText mEdtPassword;
    private TextView mTxtSubmit;

    @Override
    public void onStop() {
        super.onStop();
        if (progressDialog != null && progressDialog.isShowing())
            progressDialog.dismiss();
        if (dialog != null && dialog.isShowing())
            dialog.dismiss();
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        View view = inflater.inflate(R.layout.fragment_change_email, container,
                false);
        mTxtCurrentEmail = (TextView) view.findViewById(R.id.current_email);
        mEdtNewEmail = (EditText) view.findViewById(R.id.edit_email);
        mEdtPassword = (EditText) view.findViewById(R.id.edit_password);
        mTxtSubmit = (TextView) view.findViewById(R.id.button_submmit);
        return view;
    }

    private void showErrorDialog(String msg) {
        Builder builder = new Builder(getActivity());
        builder.setTitle(getString(R.string.fg_change_email_dialog_error_title));
        builder.setMessage(msg);
        builder.setNegativeButton(getText(R.string.common_ok), null);
        dialog = builder.create();
        dialog.show();
    }
}

我的活动代码:

@Override
    public void onStop() {
        super.onStop();
        InputMethodManager imm = (InputMethodManager) getSystemService(
              Context.INPUT_METHOD_SERVICE);
        imm.hideSoftInputFromWindow(mEdtUserName.getWindowToken(), 0);
    }

Answer 1

试试这种方式 Fragment

 InputMethodManager imm = (InputMethodManager)getActivity().getSystemService(Context.INPUT_METHOD_SERVICE);
 imm.hideSoftInputFromWindow(getView().getWindowToken(), 0);