rud*_*yle 1 php email yahoo gmail codeigniter
我有一些问题,我不明白.这是我的代码
$this->load->library('email');
$config['protocol'] = 'sendmail';
$config['mailpath'] = '/usr/sbin/sendmail';
$config['charset'] = 'iso-8859-1';
$config['wordwrap'] = TRUE;
$this->email->initialize($config);
$this->email->from('rudzstyle@yahoo.co.id', 'Your Name');
$this->email->to('rudzstyle@gmail.com');
$message = $data->nama_depan.'<br>'.$this->input->post('snk');
$this->email->subject($message);
$this->email->message('Testing the email class.');
$this->email->send();
echo $this->email->print_debugger();
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那2封电子邮件是有效电子邮件
调试器的结果就是这个
退出状态码:1无法打开Sendmail的套接字.请检查设置.无法使用PHP Sendmail发送电子邮件.您的服务器可能未配置为使用此方法发送邮件.
User-Agent:CodeIgniter日期:星期一,2014年6月2日07:53:21 +0200来自:"你的名字"返回路径:收件人:rudzstyle@gmail.com主题:=?iso-8859-1?Q?Riyanto test ?= =?iso-8859-1?Q ?? =回复:"rudzstyle@yahoo.co.id"X-Sender:rudzstyle@yahoo.co.id X-Mailer:CodeIgniter X-Priority:3(正常)消息ID:<538c1151179cb@yahoo.co.id> Mime版本:1.0
内容类型:text/plain; charset = iso-8859-1 Content-Transfer-Encoding:8bit
测试电子邮件类.
在Codeigniter中,试试这个
$this->load->library('email');
$config['protocol']='smtp';
$config['smtp_host']='your host';
$config['smtp_port']='465';
$config['smtp_timeout']='30';
$config['smtp_user']='your mail id';
$config['smtp_pass']='your password';
$config['charset']='utf-8';
$config['newline']="\r\n";
$config['wordwrap'] = TRUE;
$config['mailtype'] = 'html';
$this->email->initialize($config);
$this->email->from('no-reply@your-site.com', 'Site name');
$this->email->to('to-address-mail-id');
$this->email->subject('Notification Mail');
$this->email->message('Your message');
$this->email->send();
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在$config['smtp_user']字段中,提供您的email_id和$config['smtp_pass']现场,提供该邮件的密码.
这将工作.只是尝试一下.希望这能解决你的问题.
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