Sam*_*aid 0 javascript json underscore.js
我试图找出如何合并两个JSON对象并基于条件创建合并对象.
我想遍历leadlistArray,获取每个条目的rules.id并将其与rulesArray匹配.最终结果应该是finalArray.
leadlistArray = {
"status": "success",
"data": {
"leadlists": [
{
"rules": [
{
"$oid": "53866d4d1fd21c3cc41f52da"
}
],
"name": "List 1: only general rule"
},
{
"rules": [
{
"$oid": "53866d4d1fd21c3cc41f52da"
},
{
"$oid": "53866d9c1fd21c3cc79bf7ce"
},
{
"$oid": "53866d9c1fd21c3cc79bf2cd"
}
],
"name": "List 2: general and web-based rule"
},
{
"rules": [
{
"$oid": "53866d9c1fd21c3cc79bf7ce"
}
],
"name": "List 3: only web-based rule"
}
]
}
}
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规则数组:
rulesArray = {
"status": "success",
"data": {
"rules": [
{
"description": "optimizely no!",
"start_time": "",
"values": [
"optimizely"
],
"end_time": "",
"operator": "",
"_id": {
"$oid": "53866d4d1fd21c3cc41f52da"
},
"type": 0,
"condition": 1
},
{
"description": "google_plus no!",
"start_time": "",
"values": [
"google_plus"
],
"end_time": "",
"operator": "",
"_id": {
"$oid": "53866d9c1fd21c3cc79bf2cd"
},
"type": 1,
"condition": 1
},
{
"description": "google_plus yes!",
"start_time": "",
"values": [
"google_plus"
],
"end_time": "",
"operator": "",
"_id": {
"$oid": "53866d9c1fd21c3cc79bf7ce"
},
"type": 1,
"condition": 0
}
]
}
}
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对于每个列表,finalArray应按规则类型对规则描述进行分组:
finalArray = [
{'name': 'List 1: only general rule'
,'rules':
{0: [
{'description': 'optimizely no!'}
]}
},
{'name': 'List 2: general and web-based rule'
,'rules':
{0: [
{'description': 'optimizely no!'}
], 1: [
{'description': 'google_plus yes!'},
{'description': 'google_plus no!'}
]}
},
{'name': 'List 3: only web-based rule'
,'rules': {
1: [
{'description': 'google_plus yes!'}
]}
}
]
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试试这个http://jsfiddle.net/eN52v/
var rules = rulesArray.data.rules
.reduce(function(acc, item){
return acc[item._id.$oid] = {
description: item.description,
type: item.type}, acc;
}, {}), //cache rules by id to avoid array lookups.
finalArray = leadlistArray.data.leadlists.map(function(item) {
return {
name: item.name,
rules: item.rules.reduce(function(acc, rule){ //Why not an array?
var ruleDesc = rules[rule.$oid],
type = ruleDesc.type;
(acc[type] || (acc[type] = [])).push({description: ruleDesc.description});
return acc;}, {})
}});
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