Java正则表达式分别匹配每个组

Question

我有一个像这样的字符串:

String text = "new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90',     '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90',     '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL')";

和正则表达式:

String regex = "new SingleSizeProduct((.*))";

我想分别匹配所有6个组,但是当我匹配模式时,我得到这样的结果:

(
[0] => new SingleSizeProduct(422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
[1] => (422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
[2] => (422056, 1265858, 5430, '3XL', 75, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265859, 5341, 'L', 55, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265860, 5459, 'M', 45, 1, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265861, 5446, 'S', 35, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265862, 5458, 'XL', 60, 0, '14.90', '16.50', '29.90', 'TL'),new SingleSizeProduct(422056, 1265863, 5511, 'XXL', 65, 0, '14.90', '16.50', '29.90', 'TL'),
)

我如何分别匹配每个组？

Answer 1

.*是贪婪的，所以它会尝试找到最大可能的匹配意味着(.*)将匹配

abc(foo)def(bar)ghi
    ^^^^^^^^^^^

如果你想让它找到最小可能的匹配

abc(foo)def(bar)ghi
    ^^^     ^^^

在其后*添加使其不情愿?

String regex = "new SingleSizeProduct((.*?))";

此外，您还需要逃脱(，)因为您知道它们代表捕获组的起点。

String regex = "new SingleSizeProduct\\((.*?)\\)";

顺便提一句。另一种解决方案是使用，而不是.*? [^)]*这意味着，除了)

String regex = "new SingleSizeProduct(([^)]*))";