从NSString解析地址而不使用NSDataDetector

Cli*_*lip 6 objective-c ios nsdatadetector

我一直在使用NSDataDetector解析字符串的地址,并且大部分它做得很好.然而,在地址'类似于这个地方它没有检测到它.

6200 North Evan Blvd Suit 487 Highland UT 84043

目前我正在使用此代码:

NSError *error = nil;
NSDataDetector *detector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeAddress error:&error];


NSArray *matches = [detector matchesInString:output options:0 range:NSMakeRange(0, [output length])];

for (NSTextCheckingResult *match in matches) {
    if ([match resultType] == NSTextCheckingTypeAddress) {

        _address = [_tesseractData substringWithRange:[match range]];
        NSDictionary *data = [match addressComponents];

        _zip = [data objectForKey:@"ZIP"];
        if (_zip) {
            NSRange zipRange = [_tesseractData rangeOfString:_zip];
            if (zipRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:zipRange];
            }
        }

        _city = [data objectForKey:@"City"];
        if (_city) {
            NSRange cityRange = [_tesseractData rangeOfString:[_city uppercaseString]];
            if (cityRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:cityRange];
            }
        }
        _city = [_city capitalizedString];

        _state = [data objectForKey:@"State"];

        _street = [data objectForKey:@"Street"];
        if (_street) {
            NSRange streetRange = [_tesseractData rangeOfString:[_street uppercaseString]];
            if (streetRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:streetRange];
            }
        }
        _street = [_street capitalizedString];

    }
}
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任何人都可以建议一个更健壮的方法来解析字符串中的物理地址吗?我需要能够获得Zip,Street,State和City.

day*_*ben 1

您可以尝试使用正则表达式(RegEx)解析地址信息,我认为这是更稳健的方式。请参阅以下参考资料来使用 RegEx:Making RegEx Easy in Objective-C ,Objective-C RegEx 类别可在GitHub上找到。