Vik*_*uli 14 string search android listview
我有一个ListView,我正在使用自定义适配器来显示数据.现在我想改变搜索文本字母颜色,如上面的屏幕截图.
这是代码 SearchView
@Override
public boolean onCreateOptionsMenu(Menu menu) {
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.actionbar_menu_item, menu);
SearchManager searchManager = (SearchManager) getSystemService(Context.SEARCH_SERVICE);
final SearchView searchView = (SearchView) menu.findItem(R.id.action_search)
.getActionView();
searchView.setSearchableInfo(searchManager
.getSearchableInfo(getComponentName()));
searchView.setOnQueryTextListener(this);
return super.onCreateOptionsMenu(menu);
}
public boolean onQueryTextChange(String newText) {
// this is adapter that will be filtered
if (TextUtils.isEmpty(newText)){
lvCustomList.clearTextFilter();
}
else{
lvCustomList.setFilterText(newText.toString());
}
return false;
}
@Override
public boolean onQueryTextSubmit(String query) {
return false;
}
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谢谢.
mat*_*ash 27
我假设您有一个自定义适配器,getCount()并getView()已实现并已经过滤项目,您只需要粗体部分.
要实现这一点,您需要使用a SpannableString,它基本上是带有标记的文本.例如,a TextAppearanceSpan可用于更改字体,字体样式,大小和颜色.
因此,您应该更新适配器getView()以将您使用的部分更改为textView.setText()或多或少的内容:
String filter = ...;
String itemValue = ...;
int startPos = itemValue.toLowerCase(Locale.US).indexOf(filter.toLowerCase(Locale.US));
int endPos = startPos + filter.length();
if (startPos != -1) // This should always be true, just a sanity check
{
Spannable spannable = new SpannableString(itemValue);
ColorStateList blueColor = new ColorStateList(new int[][] { new int[] {}}, new int[] { Color.BLUE });
TextAppearanceSpan highlightSpan = new TextAppearanceSpan(null, Typeface.BOLD, -1, blueColor, null);
spannable.setSpan(highlightSpan, startPos, endPos, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
textView.setText(spannable);
}
else
textView.setText(itemValue);
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