pyy*_*pyy 8 sql hibernate jpa named-query spring-data-jpa
使用Oracle 11g的spring data jpa 1.4.3.
我有这样一个实体:
class LinkRecord {
String value;
int linkType;
...
}
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我使用(value,linkType)作为复合索引.对于给定的(v,t)元组列表,我们需要选择DB中的所有记录,以便value = v,linkType = t.
基本上,我想构建此查询:
SELECT * FROM LINK_RECORD WHERE (VALUE, LINK_TYPE) IN (('value1', 0), ('value2', 25), ...)
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IN子句中的列表作为参数传入的位置.
由于我们正在处理大量数据,因此逐个查询元组是非常不可取的.
在我的存储库中我试过这个:
@Query("select r from LinkRecord r where (r.value, r.linkType) in :keys")
List<LinkRecord> findByValueAndType(@Param("keys")List<List<Object>> keys);
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其中keys是一个列表(长度为2的列表).这让我得到ORA_00920:无效的关系运算符.
有没有办法使用命名查询来完成这项工作?或者我是否必须使用本机sql?
谢谢你的帮助.
答案为时已晚,但也许其他人也有同样的问题。这是我的工作示例之一。在这里,我需要搜索与给定组合键匹配的所有条目:
实体....
@Entity
@NamedQueries({
@NamedQuery(name = "Article.findByIdAndAccessId", query = "SELECT a FROM Article a WHERE a.articlePk IN (:articlePks) ORDER BY a.articlePk.article")
})
@Table(name = "ARTICLE")
public class Article implements Serializable
{
private static final long serialVersionUID = 1L;
@EmbeddedId
private ArticlePk articlePk = new ArticlePk();
@Column(name = "art_amount")
private Float amount;
@Column(name = "art_unit")
private String unit;
public Article()
{
}
//more code
}
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PK课……
@Embeddable
public class ArticlePk implements Serializable
{
private static final long serialVersionUID = 1L;
@Column(name = "art_article")
private String article;
@Column(name = "art_acc_identifier")
private Long identifier;
public ArticlePk()
{
}
public ArticlePk(String article, Long identifier)
{
this.article = article;
this.identifier = identifier;
}
@Override
public boolean equals(Object other)
{
if (this == other)
{
return true;
}
if (!(other instanceof ArticlePk))
{
return false;
}
ArticlePk castOther = (ArticlePk)other;
return this.article.equals(castOther.article) && this.identifier.equals(castOther.identifier);
}
@Override
public int hashCode()
{
final int prime = 31;
int hash = 17;
hash = hash * prime + this.article.hashCode();
hash = hash * prime + this.identifier.hashCode();
return hash;
}
//more code
}
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调用由....
TypedQuery<Article> queryArticle = entityManager.createNamedQuery("Article.findByIdAndAccessId", Article.class);
queryArticle.setParameter("articlePks", articlePks);
List<Article> articles = queryArticle.getResultList();
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在哪里....
articlePks是List<ArticlePk>。
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