pyy*_*pyy 8 sql hibernate jpa named-query spring-data-jpa
使用Oracle 11g的spring data jpa 1.4.3.
我有这样一个实体:
class LinkRecord {
  String value;
  int linkType;
  ...
}
我使用(value,linkType)作为复合索引.对于给定的(v,t)元组列表,我们需要选择DB中的所有记录,以便value = v,linkType = t.
基本上,我想构建此查询:
SELECT * FROM LINK_RECORD WHERE (VALUE, LINK_TYPE) IN (('value1', 0), ('value2', 25), ...)
IN子句中的列表作为参数传入的位置.
由于我们正在处理大量数据,因此逐个查询元组是非常不可取的.
在我的存储库中我试过这个:
@Query("select r from LinkRecord r where (r.value, r.linkType) in :keys")
List<LinkRecord> findByValueAndType(@Param("keys")List<List<Object>> keys);
其中keys是一个列表(长度为2的列表).这让我得到ORA_00920:无效的关系运算符.
有没有办法使用命名查询来完成这项工作?或者我是否必须使用本机sql?
谢谢你的帮助.
答案为时已晚,但也许其他人也有同样的问题。这是我的工作示例之一。在这里,我需要搜索与给定组合键匹配的所有条目:
实体....
@Entity
@NamedQueries({
    @NamedQuery(name = "Article.findByIdAndAccessId", query = "SELECT a FROM Article a WHERE a.articlePk IN (:articlePks) ORDER BY a.articlePk.article")
})
@Table(name = "ARTICLE")
public class Article implements Serializable
{
    private static final long serialVersionUID = 1L;
    @EmbeddedId
    private ArticlePk articlePk = new ArticlePk();
    @Column(name = "art_amount")
    private Float amount;
    @Column(name = "art_unit")
    private String unit;
    public Article()
    {
    }
    //more code
}
PK课……
@Embeddable
public class ArticlePk implements Serializable
{
    private static final long serialVersionUID = 1L;
    @Column(name = "art_article")
    private String article;
    @Column(name = "art_acc_identifier")
    private Long identifier;
    public ArticlePk()
    {
    }
    public ArticlePk(String article, Long identifier)
    {
        this.article = article;
        this.identifier = identifier;
    }
    @Override
    public boolean equals(Object other)
    {
        if (this == other)
        {
            return true;
        }
        if (!(other instanceof ArticlePk))
        {
            return false;
        }
        ArticlePk castOther = (ArticlePk)other;
        return this.article.equals(castOther.article) && this.identifier.equals(castOther.identifier);
    }
    @Override
    public int hashCode()
    {
        final int prime = 31;
        int hash = 17;
        hash = hash * prime + this.article.hashCode();
        hash = hash * prime + this.identifier.hashCode();
        return hash;
    }
    //more code
}
调用由....
TypedQuery<Article> queryArticle = entityManager.createNamedQuery("Article.findByIdAndAccessId", Article.class);
queryArticle.setParameter("articlePks", articlePks);
List<Article> articles = queryArticle.getResultList();
在哪里....
articlePks是List<ArticlePk>。
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