Rspec匹配哈希数组

Question

我有一个哈希数组,为了论证的缘故,这样:

[{"foo"=>"1", "bar"=>"1"}, {"foo"=>"2", "bar"=>"2"}]

使用Rspec,我想测试"foo" => "2"数组中是否存在,但我不在乎它是第一项还是第二项.我试过了:

[{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}].should include("foo" => "2"))

但这不起作用,因为哈希应该完全匹配.有没有办法部分测试每个哈希的内容？

Answer 1

怎么样？

hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes).to include(include('foo' => '2'))

Answer 2

您可以使用该any?方法.见这对于文档.

hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes.any? { |hash| hash['foo'] == '2' }).to be_true

Answer 3

您可以使用可组合匹配器

http://rspec.info/blog/2014/01/new-in-rspec-3-composable-matchers/

但我更喜欢像这样定义自定义匹配器

require 'rspec/expectations'

RSpec::Matchers.define :include_hash_matching do |expected|
  match do |array_of_hashes|
    array_of_hashes.any? { |element| element.slice(*expected.keys) == expected }
  end
end

并在这样的规格中使用它

describe RSpec::Matchers do
  describe '#include_hash_matching' do
    subject(:array_of_hashes) do
      [
        {
          'foo' => '1',
          'bar' => '2'
        }, {
          'foo' => '2',
          'bar' => '2'
        }
      ]
    end

    it { is_expected.to include_hash_matching('foo' => '1') }

    it { is_expected.to include_hash_matching('foo' => '2') }

    it { is_expected.to include_hash_matching('bar' => '2') }

    it { is_expected.not_to include_hash_matching('bar' => '1') }

    it { is_expected.to include_hash_matching('foo' => '1', 'bar' => '2') }

    it { is_expected.not_to include_hash_matching('foo' => '1', 'bar' => '1') }

    it 'ignores the order of the keys' do
      is_expected.to include_hash_matching('bar' => '2', 'foo' => '1')
    end
  end
end


Finished in 0.05894 seconds
7 examples, 0 failures

Answer 4

使用可组合的匹配器

hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes).to match([a_hash_including('foo' => '2'), a_hash_including('foo' => '1')])