ContentResolver和"IN"语句在"where"条件下

Ana*_*ion 4 java android

我正在尝试基于therir id获取光标以获取联系人列表.我不确定如何使用带有参数数组的"IN"语句.我目前有什么导致错误.

public Cursor GetContacts(String[] ids)
{
    ContentResolver cr = getContentResolver();

    try
    {
        Uri uri = ContactsContract.Contacts.CONTENT_URI;

        String[] projection = new String[] {
                ContactsContract.Contacts._ID,
                ContactsContract.Contacts.DISPLAY_NAME,
                ContactsContract.Contacts.HAS_PHONE_NUMBER
        };

        String where = ContactsContract.Contacts._ID + " IN ?";

        String[] selectionArgs = ids;

        String sortOrder = ContactsContract.Contacts.DISPLAY_NAME;

        return cr.query(uri, projection, where, selectionArgs, sortOrder);
    }
    catch (Exception ex)
    {
    String message = ex.getMessage();
    Log.e("mine", "Error: " + message, ex);

    return null;
    }
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错误:接近"?":语法错误(代码1):,编译时:SELECT _id,display_name,has_phone_number FROM view_contacts WHERE((1))AND((_id IN?))ORDER BY display_name

Lar*_*zie 7

我没有测试这个,但我认为你需要将你的id压缩成一个逗号分隔的字符串,以便将它插入到你的查询中.

public Cursor GetContacts(String[] ids)
{
    ContentResolver cr = getContentResolver();

    try
    {
        Uri uri = ContactsContract.Contacts.CONTENT_URI;

        String[] projection = new String[] {
                ContactsContract.Contacts._ID,
                ContactsContract.Contacts.DISPLAY_NAME,
                ContactsContract.Contacts.HAS_PHONE_NUMBER
        };

        String where = ContactsContract.Contacts._ID + " IN (?)";

        String[] selectionArgs = {StringUtils.join(ids, ", ")};

        String sortOrder = ContactsContract.Contacts.DISPLAY_NAME;

        return cr.query(uri, projection, where, selectionArgs, sortOrder);
    }
    catch (Exception ex)
    {
    String message = ex.getMessage();
    Log.e("mine", "Error: " + message, ex);

    return null;
    }
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