sed或awk多行替换

Question

我试图将格式添加到所有/*TODO:...*/标签,但我在多行区域遇到问题.我可以做单线sed; 但对于多线sed和awk,我不知道.

我该怎么做呢？我愿意接受.这是我到目前为止所拥有的.

sed 's/\/\/\*[ \t]*TODO[ \t]*:.*/*\//<span style="color:#aaaaaa;font-weight:bold;">&</span>/g'

替换:

int void main ( int h, char * argv[] )
  int a, b; /* TODO :
               - include libraries
               ...
            */
  foobar();
  /* TODO : fix missing {'s */

用:

int void main ( int h, char * argv[] )
  int a, b; <span style="color:#aaaaaa; font-weight:bold;">/* TODO :
               - include libraries
               ...
            */</span>
  foobar();
  <span style="color:#aaaaaa; font-weight:bold;">/* TODO : fix missing {'s */ </span>

Answer 1

gawk 'BEGIN{
  RS="*/"
  replace="<span style=\"color:#aaaaaa; font-weight:bold;\">"
}
/\/\* +TODO/{
    gsub(/\/\* +TODO/,replace" /* TODO")
    RT=RT "</span>"
}
{ print $0RT}
' file

输出

$ ./shell.sh
int void main ( int h, char * argv[] )
  int a, b; <span style="color:#aaaaaa; font-weight:bold;"> /* TODO :
               - include libraries
               ...
            */</span>

  foobar();
  <span style="color:#aaaaaa; font-weight:bold;"> /* TODO : fix missing {'s */</span>